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Black_prince [1.1K]
3 years ago
6

25 POINTS TO WHOEVER CAN FILL THIS OUT! Radioactivity Decay

Chemistry
1 answer:
Degger [83]3 years ago
3 0

Answer:

how long?

Explanation:

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Is mass conserved when 40 g of sodium hydroxide undergoes a chemical change during an interaction with 37g of hydrogen chloride?
DENIUS [597]

Answer:

Mass is conserverd

Explanation:

Any chemical reaction must follow the law of conservation of mass. Meaning that mass cannot be created nor destroyed. Since all chemical reactions must follow this law, no matter what reaction happens, mass is conserved.

7 0
3 years ago
Choose the correct statement regarding the relative size of atoms:
Sonbull [250]

Answer:

The atoms on left side are larger than the atoms on the right side of the periodic table because those on the right have more proton's.

Explanation:

As we travel along a period in a periodic table then the atomic radii decreases

This is because as we travel along a period we have that the atomic number of the atoms increases which means the the number of proton's increased

But the electron's add to the same outer shell throughout the period , which means the effective nuclear charge increases which pulls the outer electrons toward's the nucleus and the size decreases.

Therefore the atoms on left side are larger than the atoms on the right side of the periodic table because those on the right have more proton's.

6 0
3 years ago
Hydroxyapatite, Ca 10 ( PO 4 ) 6 ( OH ) 2 , has a solubility constant of Ksp = 2.34 × 10 − 59 , and dissociates according to Ca
GenaCL600 [577]

Answer: 4M

Explanation:

5 0
3 years ago
Which of these types of changes is a physical change?
Cloud [144]

Answer:

answer is c

Explanation: cause there breaking it

8 0
3 years ago
Hydrogen 3 has a half life of 12.32 years a sample of h-3 weighing 3.02 grams is left for 15.0 years what will the final weight
yawa3891 [41]

Answer:

The final mass of sample is 1.3 g.

Explanation:

Given data:

Half life of H-3 = 12.32 years

Amount left for 15.0 years = 3.02 g

Final amount = ?

Solution:

First all we will calculate the decay constant.

t₁/₂ = ln² /k

t₁/₂ =12.32 years

12.32 y =  ln² /k

k = ln²/12.32 y

k = 0.05626 y⁻¹

Now we will find the original amount:

ln (A°/A) = Kt

ln (3.02 g/ A) = 0.05626 y⁻¹ × 15.0 y

ln (3.02 g/ A) = 0.8439

3.02 g/ A = e⁰°⁸⁴³⁹

3.02 g/ A = 2.33

A = 3.02 g/ 2.33

A = 1.3 g

The final mass of sample is 1.3 g.

8 0
3 years ago
Read 2 more answers
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