What is responsible for the diffrence in the climate between northern and southern switzerland?

2. A sample of table sugar (sucrose, C12H22O11) has a mass of 1.202 g.

Snezhnost [94]

Explanation:

Given mass of sugar = 1.202 g

Molar mass of the sugar , $C_{12}H_{22}O_{11}$ = 342.29 g/mol

a) Number of moles of sugar

$\text{number of moles}=\frac{\text{given mass of sugar}}{\text{molar mass of sugar}}=\frac{1.202 g}{342.29g/mol}=0.0035 mol$

Number of moles of sugar in 1.202 grams is 0.0035 moles

b)Moles of each element in $C_{12}H_{22}O_{11}$

In a molecular formula of sugar there are 12 carbon, 22 hydrogen and 11 oxygen atoms

Moles of an element in molecule =

number of atoms of that element in a molecular formula × number of moles of compound

Moles of carbon = 12 × 0.0035 = 0.042 moles

Similarly

Moles of hydrogen = 22 × 0.0035 = 0.077 moles

Moles of oxygen =11 × 0.0035 = 0.0385 moles

c) Number of atoms of each type in $C_{12}H_{22}O_{11}$

$\text{Number of atoms}=\text{number of moles of that atom in a molecular formula}\times \text{Avogadro number}$

Number of carbon atoms = $0.042 mole\times 6.022 \times 10^{23}=2.52\times 10^{22} atoms$

Number of hydrogen = $0.077mole\times 6.022 \times 10^{23}=4.63\times 10^{22} atoms$

Number of oxygen atoms = $0.0385 mole\times 6.022 \times 10^{23}=2.31\times 10^{22} atoms$

7 0

3 years ago

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A 410 L volume of nitrogen gas is cooled from 61 C to -25 C. What is the volume of the nitrogen at the lower temperature if all

Lena [83]

Answer:

$304.5\text{L}$

Explanation:

Here, we want to get the volume of the nitrogen gas at the lower temperature

From Charles' law, we know that volume and temperature (in Kelvin) are directly proportion

The mathematical relationship is:

$\frac{V_1}{T_1}\text{ = }\frac{V_2}{T_2}$

Where:

V1 is the initial volume which is 410 L

V2 is the final volume which is unknown

T1 is the initial temperature which we will convert to Kelvin by adding 273.15 K, we have it as 61 + 273.15 = 334.15 K

T2 is the final temperature which we have to convert to Kelvin by adding it to 273.15K : We have that as -25 + 273.15 = 248.15 K

Substituting the values, we have it that:

$\begin{gathered} \frac{410}{334.15}\text{ = }\frac{V_2}{248.15} \\ \\ V_2\text{ = }\frac{248.15\text{ }\times410}{334.15} \\ \\ V_2\text{ = 304.5 L} \end{gathered}$

6 0

2 years ago

When light cannot travel trough a material, the light has been

Yuki888 [10]

The answer would be absorbed

8 0

3 years ago

Which properties, physical or chemical, were most useful in identifying the mystery powder? Explain your answer.

r-ruslan [8.4K]

The answer depends on what substances you were testing, but here are some ideas.

If all of them were white as in the typical experiment, then color is not very useful. If you were allowed to taste them, then a salty taste would be a helpful clue. If the textures were different, some crystals, like salt or sugar and others powdery, like flour or cornstarch, those properties would be helpful. If some dissolved in water,...

5 0

3 years ago

The element europium exists in nature as two isotopes: 151eu has a mass of 150.9196 amu, and 153eu has a mass of 152.9209 amu. t

Ratling [72]

Two isotopes of europium are 151eu and 153eu

Mass of 151eu = 150.9196 amu

Mass of 153eu = 152.9209 amu

Average atomic mass = 151.96 amu

Let x and y are the relative abundance of two isotopes of europium are 151eu and 153eu

So, x% times 150.9196 + y% times 152.9209 = 151.96

x150.9196 + y152.9209 = 151.96

And x + y = 100% = 1, from here x = 1 – y and y = 1 - x

Solve these equation by substitution,

By replacing x = 1-y, we get

(1-y)150.9196 + y152.9209 = 151.96

150.9196 – 150.9196y + y152.9209 = 151.96

2.0013y = 1.0404

Y =0.5199 = 51.99%

Using the value of y we get,

X = 1-y = 1-51.99 = 0.4801 = 48.01%

<span>So, relative abundance of two isotopes of europium are 151eu and 153eu are 48.01% and 51.99% respectively</span>

6 0

3 years ago

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