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ExtremeBDS [4]
2 years ago
9

Rank the following from smallest to largest atomic/ionic radius.

Chemistry
1 answer:
salantis [7]2 years ago
4 0

Answer:

Na+<Na< Na- (r- > r > r+)

B)O<N<C (The atomic radius of atoms generally decreases from left to right across a period)

C)Ar<cl<K

D)Be<Mg<Ca (generallydown the group atomic radius increases)

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If the volume of a confined gas is doubled while the temperature remain constant, what change (if any) would be observed in the
dimulka [17.4K]

The gas will obey Boyles Law:

P1 V1 = P2 V2      where P1 and V1 are the original pressure and volume and P2 and V2 are the new  values.

If V2 = 2V1  (given) then:

P1 V1 = P2 *2 V1

P2 = P1 V1 / 2V1

P2 = P1 / 2

In other words the pressure is halved. (answer).

3 0
3 years ago
Read 2 more answers
Consider a series of molecules in which the C atom is bonded to atoms of second-period elements: C-O, C-F, C-N, C-C, and C-B. Pl
Sati [7]

Answer:

  1. C-B
  2. C-C
  3. C-N
  4. C-O
  5. C-F

Explanation:

As we move along to the <u>right in the same period, the electronegativity</u> and <u>the effective nuclear charge values are higher.</u>

The tendency is that <em>the higher these values are, the shorter the bonds will be</em>.

With that information in mind, and looking at the periodic table, the order would be:

  1. C-B
  2. C-C
  3. C-N
  4. C-O
  5. C-F

Where the C-F bond is the shortest among them.

8 0
3 years ago
5. Which of the following can be classified as a mixture ?
podryga [215]

5. B air is a mixture of many elements, but is not a chemically fused.


6. B Beef stew, composition varies throughout.


7. A. They can be chemically separated into their component elements, but they are all homogenous, and as such, have constant composition, which differs from the components properties, as the components must undergo a chemical change to become compounds.

5 0
3 years ago
You wish to add 5 mg/l naocl as cl2 to a solution in a disinfection test, and you have a stock solution (household bleach) that
Alecsey [184]

Answer: -

0.1 ml of bleach should be added to each liter of test solution.

Explanation:-

Let the volume of bleach to be added is B ml.

Density of stock solution = 1.0 g/ml

Mass of stock solution = Volume of stock x density of stock

                                     = B ml x 1.0 g/ml

                                     = B g

Amount of NaOCl in this stock solution = 5% of B g

                                     = \frac{5}{100} x B g

                                     = 0.05 B g

Now each test solution must be added 5 mg/l NaOCl.

Thus each liter of test solution must have 5 mg.

Thus 0.05 B g = 5 mg

                        = 0.005 g

B = \frac{0.005}{0.05}

  = 0.1

Thus 0.1 ml of bleach should be added to each liter of test solution.

4 0
2 years ago
Is drawing on paper a chemical or physical change
Tatiana [17]

Answer:5

Explanation:

3 0
2 years ago
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