Answer:
1.05 x 103s
Explanation:
The answer to the question is 1.05 x 103s
As the banana flies through space, up the red arrow showing its path of motion takes a curved or parabolic shape.
<h3>What is a projectile?</h3>
A projectile is an object launched into space at an angle to the horizontal ground and allowed to fall freely under gravity.
The path of motion of a projectile is parabolic.
Examples of objects that are projectiles include:
- A thrown banana
- A kicked football
- An arrow shot from a bow
Therefore, as the banana flies through space, up the red arrow showing its path of motion takes a curved or parabolic shape.
Learn more about projectiles at: brainly.com/question/24216590
The tension in each of the ropes is 625 N.
Draw a free body diagram for the bag of food as shown in the attached diagram. Since the bag hangs from the midpoint of the rope, the rope makes equal angles θ with the horizontal. The tensions <em>T</em> in both the ropes are also equal.
Resolve the tension T in the ropes into horizontal and vertical components T cosθ and T sinθ respectively, as shown in the figure. At equilibrium,
......(1)
Calculate the value of sinθ using the right angled triangles from the diagram.

Substitute the value of sinθ in equation (1) and simplify to obtain T.

Thus the tension in the rope is 625 N.
Answer:
The Amount of work is done on the box by the net force is 378 Joules.
Explanation:
Given:
A 42 N net force is applied to a box which slides horizontally across a floor.
Force = 42 N
Force applied for a displacement of 9.0 m
Displacement = 9.0 m
To Find:
Amount of work is done on the box by the net force = ?
i.e Work = ?
Solution:
When a force causes a object to move, work is being done on the object by the force. Work is the measure of energy transfer when a force (F) moves an object through a distance (d).
Formula is given by

Substituting the given values we get
∴ Work = 42 × 9.0
∴ Work = 378 N-m
or
∴ Work = 378 Joules
The Amount of work is done on the box by the net force is 378 Joules.
Answer:
dado os monômios X elevado a 2 + 2 elevado a 2 menos 6 elevado a 2 a redução dos monômios está representado na questão em que os monômios a seguir eles representam quatro graus dê valor numérico da expressão m + n = 20 x elevado a 7 Y.