Answer:
velocity = 472 m/s
velocity = 52.4 m/s
Explanation:
given data
steady rate = 0.750 m³/s
diameter = 4.50 cm
solution
we use here flow rate formula that is
flow rate = Area × velocity .............1
0.750 = × (4.50×
)² × velocity
solve it we get
velocity = 472 m/s
and
when it 3 time diameter
put valuer in equation 1
0.750 = × 3 × (4.50×
)² × velocity
velocity = 52.4 m/s
Answer:
a) If the mass is doubled, then the period is increased by . Hence, the period of the system is 2.828 seconds.
b) If the mass is halved, then the period is reduced by . Hence, the period of the system is 1.414 seconds.
c) The period of the system does not depend on amplitude. Hence, the period of the system is 2 seconds.
d) If the spring constant is doubled, then the period is reduced by . Hence, the period of the system is 1.414 seconds.
Explanation:
The statement is incomplete. We proceed to present the complete statement: <em>A block attached to a spring with unknown spring constant oscillates with a period of 2.00 s. What is the period if </em><em>a. </em><em>The mass is doubled? </em><em>b.</em><em> The mass is halved? </em><em>c.</em><em> The amplitude is doubled? </em><em>d.</em><em> The spring constant is doubled? </em>
We have a block-spring system, whose angular frequency () is defined by the following formula:
(1)
Where:
- Spring constant, measured in newtons per meter.
- Mass, measured in kilograms.
And the period (), measured in seconds, is determined by the following expression:
(2)
By applying (1) in (2), we get the following formula:
a) If the mass is doubled, then the period is increased by . Hence, the period of the system is 2.828 seconds.
b) If the mass is halved, then the period is reduced by . Hence, the period of the system is 1.414 seconds.
c) The period of the system does not depend on amplitude. Hence, the period of the system is 2 seconds.
d) If the spring constant is doubled, then the period is reduced by . Hence, the period of the system is 1.414 seconds.
Answer:6.298,4.1,1.9015
Explanation:
Wavelength=
==4.397 m
Distance of 3rd speaker from speaker A is x
From B 78-x
Difference between the distances must be a whole number of wavelengths
First
for 1 st wavelength
2x=8.2+4.397=12.597
x=6.298m
second
For zero wavelength
2x=8.2
x=4.1m
Third
x=1.9015 m
The final velocity of the bullet+block is 0.799 m/s
Explanation:
We can solve this problem by applying the principle of conservation of momentum: in fact, the total momentum of the bullet-block system must be conserved before and after the collision.
Mathematically, we can write:
where
m = 0.001 kg is the mass of the bullet
u = 800 m/s is the initial velocity of the bullet
M = 1 kg is the mass of the block
U = 0 is the initial velocity of the block (initially at rest)
v is the final combined velocity of the bullet and the block
Solving the equation for v, we find the final velocity:
Learn more about conservation of momentum:
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