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Elena L [17]
3 years ago
15

Write a question about how changing temperature affects the gas inside the sports ball

Physics
1 answer:
dmitriy555 [2]3 years ago
6 0

Answer:

What happens to the pressure of the air inside a sport ball when it is heated?

Explanation:

We can answer this question by thinking at what happen at microscopic level.

In fact, when the gas inside the ball is heated, the molecules of the gas start moving faster. As a result, the rate of collision of the molecules against the internal surface of the ball increases: and therefore, the pressure of the gas inside the ball increases.

We can also see this by looking at the ideal gas law, which states that:

pV=nRT

where

p is the gas pressure

V is the gas volume

n is the number of moles

R is the gas constant

T is the absolute temperature of the gas

In this situation, the volume of the gas V is constant (since the ball has a constant volume), the number of moles n is also constant, as well as R. So we can rewrite this as

p \propto T

so we see that the pressure is directly proportional to the temperature: therefore, when the ball is heated, the pressure inside the ball increases.

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In a tropic level, energy flows from the producer to the primary consumer and to a secondary consumer. True False
Ganezh [65]

Answer:

True

Explanation:

This is true because in an energy flow, the primary producers such as plants produce their own foods by using energy from the sun. These primary producers are consumed by primary consumers such as rabbits for food, while secondary consumers such as snakes would consume the primary consumers.

By so doing, energy flows from one trophic level to the other.

4 0
3 years ago
9) If a wave has a speed of 362 m/s and a period of 4.17 s, what is its wavelength?
kakasveta [241]

Answer:

Option B (1.51 m)

Explanation:

U 2 can help me by marking as brainliest........

5 0
2 years ago
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Monochromatic light of wavelength 385 nm is incident on a narrow slit. On a screen 3.00 m away, the distance between the second
LiRa [457]

To solve this problem it is necessary to apply the concepts related to the concept of overlap and constructive interference.

For this purpose we have that the constructive interference in waves can be expressed under the function

a sin\theta = m\lambda

Where

a = Width of the slit

d = Distance of slit to screen

m = Number of order which represent the number of repetition of the spectrum

\theta = Angle between incident rays and scatter planes

At the same time the distance on the screen from the central point, would be

sin\theta = \frac{y}{d}

Where y = Represents the distance on the screen from the central point

PART A ) From the previous equation if we arrange to find the angle we have that

\theta = sin^{-1}(\frac{y}{d})

\theta = sin^{-1}(\frac{1.4*10^{-2}}{3})

\theta = 0.2673\°

PART B) Equation both equations we have

a sin\theta = m\lambda

a \frac{y}{d} = m\lambda

Re-arrange to find a,

a = \frac{(2)(385*10^{-9})(3)}{(1.4*10^{-2})}

a = 1.65*10^{-4}m

8 0
3 years ago
The gravitational force of a star on an orbiting planet 1 is f1. planet 2, which is three times as massive as planet 1 and orbit
vovikov84 [41]

Gravitational force is given by, F= G\frac{mM}{R^{2}}

Where, m and M are the masses of the objects, R is the distance between them and G gravitational constant.

Gravitational force of the star on planet 1, F_{1}= G\frac{m_{1}M}{R^{2}}

Gravitational force of the star on planet 2, F_{2}= G\frac{3m_{1}M}{(3R)^{2}}

Ratio, \frac{F_{1}}{F_{2}}= \frac{\frac{Gm_{1}M}{R^{2}}}{\frac{G3m_{1}M}{(3R)^{2}}}

\frac{F_{1}}{F_{2}}=  \frac{3}{1}

Therefore, the gravitational force of the star on the planet 1 is three times that on planet 2.

6 0
3 years ago
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What is the kinetic energy in joules of a 0.05. kg bullet traveling 310 m/s
Wittaler [7]
The formula is=1/2(m x v^2)

so = 1/2*(0.05)*(310)^2

ans is =2402.5 joules
3 0
3 years ago
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