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Leni [432]
3 years ago
15

They enjoy being alone for quit small time​

Physics
1 answer:
hjlf3 years ago
4 0
Yeah and? What’s the question
You might be interested in
A car traveling at 38 m/s starts to decelerate steadily. It comes to a complete stop in 10 seconds. What is its acceleration?
asambeis [7]

a=v/t

a=38/10

a=-3.8 m/s^2

You put the negative in front of 3.8 because it decelerated.

Hope it helps and is correct :)

6 0
3 years ago
A large glass marble is added to the displacement can. 20 3 of water overflows into a beaker, and the displacement can now has a
IRISSAK [1]

The density of the glass can be determined using the formula:

  • Density of the glass = (Mf - Mi)/20 cm³

<h3>What is density?</h3>

Density is defined as the ratio of mass and volume of a substance.

  • Density = mass/volume

The mass of the glass = Final mass of beaker  - initial mass  of beaker (Mf - Mi)

The initial mass of the beaker is not given.

Volume of the glass marble = 20 cm³

Density of the glass = (Mf - Mi)/20 cm³

Therefore, the density of the glass is determined from the ratio of the mass and volume of the glass.

Learn more about density at: brainly.com/question/1354972

#SPJ1

6 0
2 years ago
A train travelling at 20 m/s has 2 000 000 J of kinetic energy. What is the mass of<br> the train?
Svetlanka [38]

Answer:

<h2>10,000 kg</h2>

Explanation:

The mass of the train can be found by using the formula

m =  \frac{2k}{ {v}^{2} }  \\

k is the kinetic energy

v is the velocity

From the question we have

m \frac{2(2000000)}{ {20}^{2} }  =  \frac{4000000}{400}  =  \frac{40000}{4}  \\

We have the final answer as

<h3>10,000 kg</h3>

Hope this helps you

3 0
3 years ago
Read 2 more answers
How long will it take a person walking at 2.1 m/s to travel 13 m?
MrRissso [65]

Answer:

I gonna give you the number so but you need to round 6.19047619048

Explanation:

  • This is a speed formula so you would use the formula speed=distance/time
  • You need to rearrange it to time=distance/speed
  • So you need to divide 13m by 2.1 m/s

7 0
3 years ago
The driver of a car slams on the brakes when he sees a tree blocking the road. the car slows uniformly with acceleration of -5.9
Hatshy [7]
Let u =  the speed of the car at the instant when braking begins.

The braking distance is s = 62.3 m, the acceleration is a = -5.9 m/s², and the braking duration is t = 4.15 s.

Use the formula s = ut + (1/2)at² to obtain
(u m/s)*(4.15 s) + 0.5*(-5.9 m/s²)*(4.5 s)² = (62.3 m)
4.15u = 62.3 + 50.8064 = 113.1064
      u = 27.2546 m/s

Let v m/s be the speed with which the car strikes the tree.
Then
v = 27.2546 - 5.9*4.15
   = 2.7696 m/s

Answer: 2.77 m/s (nearest hundredth)

4 0
3 years ago
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