(a) The emf induced in the wire is 0.112 V.
(b) The direction of the current will into the page.
(c) The polarity of A will be positive and L will be negative.
(d) The current flowing through the wire is 0.224 A.
<h3>
EMF induced in the wire</h3>
The emf induced in the wire is calculated as follows;
EMF = BLv
EMF = (8 x 10⁻²) x 0.2 x 7
EMF = 0.112 V
<h3>Direction of the current</h3>
Since, the magnetic field is out of the page, the current will follow counter clockwise and will point into the page.
<h3>Polarity of point A and point L</h3>
The current is flowing counter currently, hence the polarity of A will be positive and L will be negative.
<h3>Current through the wire</h3>
V = IR
I = V/R
I = (0.112)/0.5
I = 0.224 A
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The velocity of pin B after rod AB has rotated through 90* is vb = 3.2549 m/s.
<h3>What is Potential and Kinetic energy?</h3>
Potential energy is the energy that is stored in any item or system as a result of its location or component arrangement. The environment outside of the object or system, such as air or height, has no impact on it. In contrast, kinetic energy refers to the energy of moving particles inside a system or an item.
mass of rod, mab = 2.4kg
mass of rod, mbc = 4kg
conservation of energy


potential energy at position 1,

V1 = 2.5 * 9.81 * 0.18 + 4 * 9.81 * 0.18
V1 = 11.30112
kinetic energy T1 at position 1 is zero
potential energy at position 2 is zero
K.E at position 2,


= 1/3 *4 * (0.36)²
=0.10368kg m²

= 1/12 *4 * (0.6)²
=0.12kg m²
on putting the values in above equation we get,
T₂ = 1.0667vb²
0 + 11.30112 = 1.0667vb² + 0
vb = 3.2549 m/s
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Answer:
it is a force
Explanation:
a force is a push or a pull