A function f(x) has solutions if we can find a value to plug in that leads to 0. In other words, there are solutions to f(x) = 0. Another term for "solution" is "root" or "x intercept"
An exponential function may cross the x axis at one point only. Though there are plenty of cases when there are no solutions at all. For instance, in the case of f(x) = (2^x) + 10
The right hand side will never be equal to zero no matter what you plug in for x. The graph will never cross the axis.
To answer your question, yes it is possible to have an exponential equation to have no solutions.
Answer:
Ur question is wrong..
Step-by-step explanation:
In a survey of 100 people, 60 like farming and 65 like civil service?
<u>60+65=125</u>..?
Answer:
4(3 * 39 – 12) = 5(2 * 39 + 6)
x = 39
Step-by-step explanation:
4(3x – 12) = 5(2x + 6)
(12x - 48) = (10x + 30)
12x - 10x = 30 + 48
2x = 78
2x/2 = x
78/2 = 39
x = 39
No Prob :)
Answer
Arc EF = 52°
Arc HD = 142°
Angle HGF = 128°
Explanation
To solve for the unknown angles, we need to first solve for x
To do that, we need to first note that the sum of angles on a straight line is 180°
So,
Angle HCG + Angle HCD = 180° (Sum of angles on a straight line)
Angle HCG = 2x
Angle HCD = 6x + 28°
Angle HCG + Angle HCD = 180°
2x + 6x + 28° = 180°
8x + 28° = 180°
8x = 180° - 28°
8x = 152°
Divide both sides by 8
(8x/8) = (152°/8)
x = 19°
Angle HCG = 2x = 2 (19°) = 38°
Angle HCD = 6x + 28° = 6(19°) + 28° = 142°
So, we can solve for the rest now
Arc EF = Angle ECF
= 90° - Angle ECD
Angle ECD = Angle HCG = 38° (Vertically opposite angles are equal)
Arc EF = Angle ECF
= 90° - Angle ECD
= 90° - 38°
= 52°
Arc HD = Angle HCD = 142°
Angle HGF = Angle HCG + Angle GCF = 38° + 90° = 128°
Hope this Helps!!!
