At the lowest point on the Ferris wheel, there are two forces acting on the child: their weight of 430 N, and an upward centripetal/normal force with magnitude n; then the net force on the child is
∑ F = ma
n - 430 N = (430 N)/g • a
where m is the child's mass and a is their centripetal acceleration. The child has a linear speed of 3.5 m/s at any point along the path of the wheel whose radius is 17 m, so the centripetal acceleration is
a = (3.5 m/s)² / (17 m) ≈ 0.72 m/s²
and so
n = 430 N + (430 N)/g (0.72 m/s²) ≈ 460 N
The ones that interact would be Atmosphere, biosphere, and cryosphere. :)
"Changing water salinity" is the most significant challenge for organisms that live in estuaries.
<u>Answer:</u> Option D
<u>Explanation:</u>
For estuaries, alkalinity levels are usually the maximum at a river's mouth where the ocean water falls for, and the minimum upstream where freshwater falls in. Although salinity vary throughout the tidal cycle. In estuaries, salinity rates usually decrease in spring as snow melt and rain raises the freshwater flow from streams and groundwater.
It influences the chemical environments within the estuary, especially the dissolved oxygen (DO) levels in the water. The level of oxygen that would get dissolved in water or its solubility get declined when the alkalinity rises.
Answer:
a)
b)
c)
d)
e)
Explanation:
Given that
d = 2 cm
V = 200 V

We know that
F = E q
F = m a
E = V/d
So
m a = q .V/d b
---------1
The mass of electron

The charge on electron

Now by putting the all values in equation 1


We know that
a)
s = 0.1 cm


b)
s = 0.5 cm


c)
s = 1 cm


d)
s = 1.5 cm


e)
s = 2 cm


Answer:
Explanation:
Start with Carbon and assume we only get 1 sugar molecule from the process.
you have 6 carbons in the sugar on the right, so you need 6 carbons on the left which only come from CO₂
6 CO₂
you have 12 hydrogen atoms in the sugar on the right, so you need 12 hydrogen atoms on the left which only come from H₂O. At 2 hydrogen atoms per water molecule means you need 6 waters.
6 CO₂ + 6 H₂O → 1 C₆H₁₂O₆
you are supplied with 12 oxygen from the CO₂ and 6 oxygen from the H₂O, but you only need 6 oxygen for the sugar. That means there are 12 oxygen remaining which will become 6 O₂ molecules
6 CO₂ + 6 H₂O → 1 C₆H₁₂O₆ + 6 O₂