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svlad2 [7]
3 years ago
15

For an independent study project, you design an experiment to measure the speed of light. You propose to bounce laser light off

a mirror that is 51.0 km due east and have it detected by a light sensor that is 135 m due south of the laser. The first problem is to orient the mirror so that the laser light reflects off the mirror and into the light sensor. Determine the angle that the normal to the mirror should make with respect to due west.
Physics
1 answer:
Gekata [30.6K]3 years ago
4 0

Answer:

4.55 minute

Explanation:

51 km = 51000 m

the ray of light travels due east 51000 m , bounces back from reflecting mirrors  . The reflected light gets focused on a point 135 m south . Let the angle between incident light and reflected light be θ.

tanθ = 135 / 51000

θ = .1516 degree

= .1516 x 60 minute

= 9.09 minute

angle between incident ray ( east - west ) and normal = 9.09 / 2

= 4.55 minute Ans

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3 years ago
A spring with spring constant 33N/m is attached to the ceiling, and a 4.8-cm-diameter, 1.5kg metal cylinder is attached to its l
mylen [45]

Answer:

0.423m

Explanation:

Conversion to metric unit

d = 4.8 cm = 0.048m

Let water density be \who_w = 1000 kg/m^3

Let gravitational acceleration g = 9.8 m/s2

Let x (m) be the length that the spring is stretched in equilibrium, x is also the length of the cylinder that is submerged in water since originally at a non-stretching position, the cylinder barely touches the water surface.

Now that the system is in equilibrium, the spring force and buoyancy force must equal to the gravity force of the cylinder. We have the following force equation:

F_s + F_b = W

Where F_s = kxN is the spring force, F_b = W_w = m_wg = \rho_w V_s g is the buoyancy force, which equals to the weight W_w of the water displaced by the submerged portion of the cylinder, which is the product of water density \rho_w, submerged volume V_s and gravitational constant g. W = mg is the weight of the metal cylinder.

kx + \rho_w V_s g = mg

The submerged volume would be the product of cross-section area and the submerged length x

V_s = Ax = \pi(d/2)^2x

Plug that into our force equation and we have

kx + \rho_w \pi(d/2)^2x g = mg

x(k + \rho_w g \pi d^2/4) = mg

x = \frac{m}{(k/g) + (\rho_w\pi d^2/4)} = \frac{1.5}{(33/9.8) + (100*\pi * 0.048^2/4)} = 0.423 m

6 0
3 years ago
An internal combustion engine uses fuel, of energy content 44.4 MJ/kg, at a rate of 5 kg/h. If the efficiency is 28%, determine
Alika [10]
Efficiency =  Power Output / Power Input

Power Input = Rate of Energy input = 44.4 MJ/kg * 5 kg/h

 = 222 MJ/h

But 1 hour = 3600seconds

222 MJ/h = 222 MJ/3600s =  0.061667 MW              J/s = Watts

Power input = 0.061667 MW = 61 667 W

From  Efficiency =  Power Output / Power Input

   28% =  Power Output / 61667

   Power Output = 0.28 * 61667

   Power Output = 17266.76 W

    Power Output ≈ 17 267 W

   Rate of heat rejection = Power Input - Power Output

                                   =  61667 - 17267 = 44400 W

   Rate of heat rejection = 44 400W.
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4 years ago
An object that gives off electromagnetic waves based on its temperature
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Answer:

B) Blackbody radiation

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3 0
3 years ago
The objective lens in a DVD player must move quickly to keep the laser beam focused on the disc's reflective layer. Why must thi
Zinaida [17]

Explanation:

The small mass of lens in a DVD player accounts for small inertia of the lens. Hence, even on application of force of small magnitude, the lens is rapidly accelerated. Moreover, the small mass of lens also accounts for lower resistance to change in its motion and therefore, again can be rapidly accelerated back and forth.

4 0
3 years ago
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