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Serggg [28]
4 years ago
8

How does changes in distance affect the gravitational pull between two objects? Describe and give one example.

Physics
1 answer:
maxonik [38]4 years ago
8 0
The formula is

F_grav = G * m1 * m2 / r^2

G m1 and m2 are going to stay the same once chosen no matter what the distance is. The only thing that will change is the distance.

As the distance increases, the Gravitational Force will decrease. It will decrease by quite a bit.

As the distance decreases, the gravitational force will Increase.

The relationship is inverse. The moon travelling around the earth is one example. The earth travelling around the sun is another.
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Which situation describes a system with decreasing gravitational potential energy?
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When developing an experimental design, which action could a scientist take to improve the quality of the result?
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Sixty identical drippers, each with a hole of diameter 1.00 mm, are used to water a yard. If the water in the main pipe of diame
VashaNatasha [74]

Answer:

a

   V =  5.30 *10^{-2} \ m^3

b

   v_1 = 0.3127 \ m/s

Explanation:

From the question we are told that

   The number of identical drippers is  n =  60

   The diameter of each hole in each dripper is  d =  1.0 \  mm =  0.001 \  m  

   The diameter of the main pipe is  d_m  =  2.5 \  cm  =  0.025 \  m

    The speed at which the water is flowing is  v  =  3.00 \  cm/s =  0.03 \  m/s

Generally the amount of water used in  one hour = 3600 seconds is mathematically represented as

          V =  A *  v  *  3600

Here A is the area of the main pipe with value

         A =  \pi  * \frac{d^2}{4}

=>       A = 3.142   * \frac{0.025^2}{4}

=>        A =  0.0004909 \  m^2

So  

=>   V =  0.0004909  *  0.03  *  3600

=>  V =  5.30 *10^{-2} \ m^3

Generally the area of the drippers is mathematically represented as

       A_1=  n  * \pi \frac{d^2}{4}

=>    A_1 =  60   * 3.142 *  \frac{0.001 ^2}{4}

=>    A_1 =  4.713 *10^{-5} \  m^2

Generally from continuity equation we have that  

         Av =  A_1 v_1

=>      0.0004909 *  0.03 =  4.713 *10^{-5} *  v_1

=>   v_1 = 0.3127 \ m/s

   

     

3 0
3 years ago
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