Answer:
The wood block reaches a height of 4.249 meters above its starting point.
Explanation:
The block represents a non-conservative system, since friction between wood block and the ramp is dissipating energy. The final height that block can reach is determined by Principle of Energy Conservation and Work-Energy Theorem. Let suppose that initial height has a value of zero and please notice that maximum height reached by the block is when its speed is zero.
![\frac{1}{2}\cdot m \cdot v^{2} = m \cdot g\cdot h + \mu_{k}\cdot m\cdot g\cdot s \cdot \sin \theta](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5Ccdot%20m%20%5Ccdot%20v%5E%7B2%7D%20%3D%20m%20%5Ccdot%20g%5Ccdot%20h%20%2B%20%5Cmu_%7Bk%7D%5Ccdot%20m%5Ccdot%20g%5Ccdot%20s%20%5Ccdot%20%5Csin%20%5Ctheta)
![\frac{1}{2}\cdot v^{2} = g\cdot h + \mu_{k}\cdot g\cdot \left(\frac{h}{\sin \theta} \right)\cdot \sin \theta](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5Ccdot%20v%5E%7B2%7D%20%3D%20g%5Ccdot%20h%20%2B%20%5Cmu_%7Bk%7D%5Ccdot%20g%5Ccdot%20%5Cleft%28%5Cfrac%7Bh%7D%7B%5Csin%20%5Ctheta%7D%20%5Cright%29%5Ccdot%20%5Csin%20%5Ctheta)
![\frac{1}{2}\cdot v^{2} = g\cdot h +\mu_{k}\cdot g\cdot h](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5Ccdot%20v%5E%7B2%7D%20%3D%20g%5Ccdot%20h%20%2B%5Cmu_%7Bk%7D%5Ccdot%20g%5Ccdot%20h)
(1)
Where:
- Maximum height of the wood block, in meters.
- Initial speed of the block, in meters per second.
- Kinetic coefficient of friction, no unit.
- Gravitational acceleration, in meters per square second.
- Mass, in kilograms.
- Distance travelled by the wood block along the wooden ramp, in meters.
- Inclination of the wooden ramp, in sexagesimal degrees.
If we know that
,
and
, then the height reached by the block above its starting point is:
![h = \frac{\left(10\,\frac{m}{s} \right)^{2}}{2\cdot (1+0.20)\cdot \left(9.807\,\frac{m}{s^{2}} \right)}](https://tex.z-dn.net/?f=h%20%3D%20%5Cfrac%7B%5Cleft%2810%5C%2C%5Cfrac%7Bm%7D%7Bs%7D%20%5Cright%29%5E%7B2%7D%7D%7B2%5Ccdot%20%281%2B0.20%29%5Ccdot%20%5Cleft%289.807%5C%2C%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%7D%20%5Cright%29%7D)
![h = 4.249\,m](https://tex.z-dn.net/?f=h%20%3D%204.249%5C%2Cm)
The wood block reaches a height of 4.249 meters above its starting point.
Question:
The question is incomplete. The mass and radius of the orbit was not added. Find below the remaining part of the question and the answer.
Rank from largest to smallest.
A) m=200 kg and L= 5000m
B) m=400 kg and L=2500m
C)m=100kg and L=2500m
D)m=100kg and L=10000m
E)m=800kg and L=5000m
F)m=300kg and L=7500m
Answer:
Fe > Ff > Fa = Fb = Fd > Fc
4*10^6 N > 2.25*10^6 > 1 *10^6 N = 1 *10^6 N = 1 *10^6 N > 0.25*10^6 N
Explanation:
The force experienced by the satellite is given by the formula;
Fc = kmL
where;
k = constant = 4π²/T²
m = mass of satellite
L = radius of orbit
Since, all the satellites complete the circular orbit in the same amount of time. The constant k does not affect the force value.
A) The force acting on satellite A from their rocket is given as follows:
Fa = kmL
Fa = 200 * 5000
= 1 *10^6 N
B) The force acting on satellite B from their rocket is given as follows:
Fb = kmL
=400 *2500
= 1*10^6 N
C) The force acting on satellite C from their rocket is given as follows:
Fc = kmL
= 100 *2500
= 0.25*10^6 N
D) The force acting on satellite D from their rocket is given as follows:
Fd = kmL
= 100 *10000
= 1*10^6 N
E) The force acting on satellite E from their rocket is given as follows:
Fe = kmL
= 800 *5000
= 4*10^6 N
F) The force acting on satellite F from their rocket is given as follows:
Ff = kmL
= 300 *7500
= 2.25*10^6 N
The ranking is given as:
Fe > Ff > Fa = Fb = Fd > Fc
4*10^6 N > 2.25*10^6 > 1 *10^6 N = 1 *10^6 N = 1 *10^6 N > 0.25*10^6 N
The answer is 3. Observation
Explanation:
The sentence "The popcorn kernels popped twice as fast as the last batch" is the result of observing or measuring the time popcorn kernels require to pop. In this context, the sentence best matches the word "observation" which the term used in the Scientific method to refer to statements that are the result of studying a phenomenon, either through the senses such as sight or through precise instruments that allow scientists to understand numerically variables such as time, speed, temperature, etc.
The galaxies are so far from the Earth, and their spectra so extremely
red-shifted, that I'm not able to see any of the items on the list.
Estimates of the Hubble constant still cover a wide range.
Let's assume that it's 70 km/sec per megaparsec, or
about 21.5 km/sec per million light years.
With that factoid, the speed of recession of each galaxy on your
invisible list is roughly
(21.5 km/sec) x (distance to the galaxy) / (1 million light years) .
You'll find ... if it's important enough to you for you to carry out the work ...
that the farthest galaxy is the fastest, the nearest one is the slowest,
and the others fall similarly in line.
In other words:
No matter where we look in the universe, and no matter
in what direction we look, we observe that:
-- all distant galaxies are moving away from us
and
-- the farther a galaxy already is from us, the faster
it's moving away from us.
This observation could have been enough to give us
a giant inferiority complex, or to cause us to go brush
our teeth and rub on some deodorant.
Motion must be defined relative to something.
Here's an obvious, everyday example:
-- You're in a passenger jet, going to visit grandma on the
coast for the holidays.
-- You're sitting still in your seat, listening to some 'mp3's,
reading a book, and dozing off.
-- At the same time, people on the ground see you flying over
at almost 500 miles per hour.
Are you moving at 500 mph, or are you not moving at all ?
The answer is 'Yes. Both.'. It just depends on who's measuring your speed.
There's no such thing as your "real" speed. Motion is always
relative to something. Different reference = different speed.