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lyudmila [28]
4 years ago
10

Consider the perbromate anion. What is the central atom? Enter its chemical symbol. How many lone pairs are around the central a

tom? What is the ideal angle between the bromine-oxygen bonds? Compared to the ideal angle, you would expect the actual angle between the bromine-oxygen bonds to be ...
Chemistry
1 answer:
Yanka [14]4 years ago
8 0

Answer:

See explanation

Explanation:

The central atom in the perbromate ion is bromine. The chemical symbol of bromine is Br. There are no lone pairs around the central bromine atom. The ion is tetrahedral in shape hence we expect a bond angle of 109°. 27 which is the ideal tetrahedral bond angle. The actual bond angle of the prebromate ion is 109.5°. The perbromate ion is BrO4^-

The observed bond angle is very close to the ideal value because of the absence of lone pairs of electrons from the central atom in the ion.

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How to determine the speed of light.
LuckyWell [14K]

Answer:

Hey mate....

Explanation:

This is ur answer....

<em>By adjusting the path length while observing the interference pattern and carefully measuring the change in path length, the wavelength of the light (λ) can be determined. The speed of light is then calculated using the equation c = λf.</em>

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4 0
3 years ago
How many sulphur atoms are there in 0.125 moles of sulphur
denpristay [2]

Explanation:

There are 6.022x1023 molecules in 1 mole of SO3 (Avogadro's number) so in 0.25 moles, there are (0.25)(6.022x1023) molecules in the 0.25 moles of SO3. or 1.506x1023 molecules per 0.25 moles of SO3.

There is one atom of sulfur in each molecule of SO3. So there are 1.506x1023 atoms of sulfur in 0.25 moles of SO3.

6 0
3 years ago
Match the definitions below with the correct component of the scientific method:
laiz [17]
A and 3

B and 6

C and 5

D and 1

E and 2

F and 4
8 0
3 years ago
The relative atomic mass of an element is
balu736 [363]

Answer:

A

Explanation:

compare it to carbon 12 I believe

3 0
3 years ago
If 10.57 g of magnesium reacts completely with 6.96 g of oxygen, what is the percent by mass of oxygen in magnesium oxide? Round
Deffense [45]

Answer:

39.7 %

Explanation:

magnesium + oxygen ⟶ magnesium oxide

   10.57 g         6.96 g               17.53 g

According to the <em>Law of Conservation of Mass</em>, the mass of the product must equal the total mass of the reactants.

Mass of MgO = 10.57 + 6.96

Mass of MgO = 17.53 g

The formula for mass percent is

% by mass = Mass of component/Total mass × 100 %

In this case,

% O = mass of O/mass of MgO × 100 %

Mass of O = 6.96 g

Mass of MgO = 17.53 g

% O = 6.96/17.53 × 100

% O = 0.3970 × 100

% O = 39.7 %

5 0
4 years ago
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