Answer:
This might be Option 2(b)
Explanation:
Answer: The term you are looking for is the word <u>Stratification</u>. It is the process in which sedimentary rocks are arranged in layers.
Hope this helps!
Answer:
<em>The revised periodic table could account for variations resulting from isotopes.</em>
Explanation:
Dmitri Mendeleev was the first person to form the periodic table.
There are certain draw backs in Mendeleev's periodic table which need to be amended.
One such problem is that Mendeleev's periodic table lacks separate place for isotopes of an element. The isotopes share the same place in his periodic table. Hence, if a revised periodic table was formed in which there are separate places for the isotopes of an element then this problem can be amended.
Answer:
1. 1.33 gram of carbon
2. 2.38g of carbon dioxide
Explanation:
From the given information:
Total amount of CO₂ = 4.86 grams
Atomic mass of C = 12 g/mole
molar mass of CO₂ = 44 g/mole
∴
The mass of the Carbon (C) in grams is:
![= Total\ amount \ of \ CO_2 \times \dfrac{12 \ g/mol}{44 \ g/mol}](https://tex.z-dn.net/?f=%3D%20Total%5C%20amount%20%5C%20of%20%5C%20CO_2%20%5Ctimes%20%5Cdfrac%7B12%20%5C%20g%2Fmol%7D%7B44%20%5C%20g%2Fmol%7D)
![= 4.86 \ g \times \dfrac{12 \ g/mol}{44 \ g/mol}](https://tex.z-dn.net/?f=%3D%204.86%20%5C%20g%20%20%5Ctimes%20%5Cdfrac%7B12%20%5C%20g%2Fmol%7D%7B44%20%5C%20g%2Fmol%7D)
= 1.33 gram of carbon
2.
Here, the total amount of CO₂ = unknown
Atomic mass of O₂ = 32 g/mole
molar mass of CO₂ = 44 g/mole
amount of oxygen = 1.73 g
∴
The mass of CO₂ = ![Total \ amount \ of \ O_2 \times \dfrac{44 \ g/mol}{32\ g/mol}](https://tex.z-dn.net/?f=Total%20%5C%20amount%20%5C%20of%20%5C%20O_2%20%5Ctimes%20%5Cdfrac%7B44%20%5C%20g%2Fmol%7D%7B32%5C%20g%2Fmol%7D)
![=1.73 \times \dfrac{44 \ g/mol}{32\ g/mol}](https://tex.z-dn.net/?f=%3D1.73%20%20%5Ctimes%20%5Cdfrac%7B44%20%5C%20g%2Fmol%7D%7B32%5C%20g%2Fmol%7D)
= 2.38 g of carbon dioxide