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8090 [49]
3 years ago
10

A chemistry student was asked to draw the electron configuration for carbon. Explain what is wrong with the electron configurati

on below. What rule did the student violate (Aufbau principle, Pauli Exclusion principle, or Hund's rule)?
1s22s23p2
Chemistry
2 answers:
alexdok [17]3 years ago
6 0
The student violated the aufbau principal as electron configurations must fill lowest energy levels before moving to the next level (3s2 comes before 3p2)
Dafna11 [192]3 years ago
4 0

Answer:

I am pretty bad at chem.

Explanation:

Im not sure.

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To form an oxygen molecule o2 two oxygen atoms share two pairs of electrons what kind of bond is shown below by the electron dot
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Which of the following is a way in which elements and compounds are similar?
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Answer:

Compound Element

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Hopefully this helps you!!!!

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How are the noble gases stable and do they exist separatly with no other element
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3 years ago
The diameter of the He He atom is approximately 0.10 nm nm . Calculate the density of the He atom in g/cm 3 g/cm3 (assuming that
Sladkaya [172]

Answer:

Density of the He atom = 12.69 g/cm³

Explanation:

From the information given:

Since 1 mole of an atom = 6.022x 10²³ atoms)

1 atom of He = 1  \ atom \times  (\dfrac{1  \ mole}{  6.022 \times  10^{23}  \ atoms}) \times ( \dfrac{4.003 \ grams}{  1  \ mole})

=6.647 \times  10^{-24} \  grams

The volume can be determined as  folows:

since the diameter of the He atom is approximately 0.10 nm

the radius of the He = \dfrac{0.10}{2} = 0.05 nm

Converting it into cm, we have:

0.05 nm \times  \dfrac{10^{-9} \  meters}{ 1  nm} \times \dfrac{ 1 cm }{10^{-2} \ meters}

=5 \times  10^{-9}  \ cm

Assuming that it is a sphere, the volume of a sphere is

= \dfrac{4}{3}\pi r^3

= \dfrac{4}{3}\pi  \times (5\times 10^{-9})^3

= 5.236 \times 10^{-25} \ cm^3

Finally, the density can be calcuated by using the formula :

Density = \dfrac{mass}{volume}

D =  \dfrac{6.647 \times  10^{-24} \  grams }{ 5.236 \times 10^{-25} \  cm^3}

D = 12.69 g/cm³

Density of the He atom = 12.69 g/cm³

4 0
3 years ago
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kirill115 [55]
Ok so, remember that t<span>he average atomic mass is what is seen on the periodic table. It is the average mass of all of the isotopes with their frequency taken into account. What you need to do is add the products of the masses and frequencies Just like this:</span>

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