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ElenaW [278]
2 years ago
7

The specific heat capacity of a pure substance can be found by dividing the heat needed to change the temperature of a sample of

the substance by the mass of the sample and by the change in temperature. The heat capacity of a certain substance has been measured to be 2.76J·g°C. Suppose 466.g of the substance are heated until the temperature of the sample has changed by 39.4°C. Write an equation that will let you calculate the heat that was needed for this temperature change. Your equation should contain only symbols.
Chemistry
1 answer:
kupik [55]2 years ago
4 0

Answer:

See below

Explanation:

ΔQ = m c T        ΔQ = heat required(J)    m = mass (g)    T = C° temp change

                             c = heat capacity in J/g-C

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Which of the following pairs of elements is most likely to form an ionic compound?
Scrat [10]

Explanation:

magnesium and sodium because they are minerals and part of iron

5 0
3 years ago
You have collected a tissue specimen that you would like to preserve by freeze drying. To ensure the integrity of the specimen,
Reika [66]

Answer:

The maximum pressure is 612.2 Pa

Explanation:

The pressure of the ice (P1) = 624 Pa

The temperature of the ice = 273.16 K

The maximum temperature the specimen = - 5 oC

                                                                     = -5 + 273 = 268K

The maximum Pressure the freeze drying can be will be (P2) = ?

Using Pressure law, which shows the relationship between pressure and temperature.

                        P1 / T1 = P2 / T2

                       P2 T1 = P1 T2

                       P2 = P1 T2 / T1

                       P2 = 624 × 268 / 273.16

                       P2 = 612.2 Pa

The maximum pressure at which drying can be carried out is 612.2 Pa

Check the attached document more explanation.   jjjjggggg

5 0
3 years ago
Could someone explain how they got this answer, explain step by step plz
gulaghasi [49]

Answer:

6.018 amu

Explanation:

Let 6–Li be isotope A.

Let 7–Li be isotope B.

Let the abundance of 6–Li be A%

Let the abundance of 7–Li be B%

The following data were obtained from the question:

Atomic mass of isotope A (6–Li) =.?

Atomic mass of isotope B (7–Li ) = 7.015 amu.

Abundance of 7–Li (B%) = 92.58%

Abundance of 6–Li (A%) = 100 – B% = 100 – 92.58 = 7.42%

Atomic mass of Lithium = 6.941amu

The atomic mass of isotope A (6–Li) can be obtained as follow:

Atomic mass = [(Mass of A x A%)/100] + [(Mass of B x B%)/100]

6.941 = [(mass of A x 7.42)/100] + [(7.015x92.58)/100]

6.941 = [(mass of A x 7.42)/100] + 6.494487

(mass of A x 7.42)/100 = 6.941 – 6.494487

(mass of A x 7.42)/100 = 0.446513

Mass of A x 7.42 = 100 x 0.446513

Mass of A x 7.42 = 44.6513

Divide both side by 7.42

Mass of A = 44.6513 / 7.42

Mass of A = 6.018 amu

Therefore, the mass of 6–Li is 6.018 amu

7 0
3 years ago
A sample with a molar mass of 34.00 g/mol is found to consist of 5.9783% Hydrogen and 94.0217% oxygen. Find it’s molecular formu
kozerog [31]

Answer:

The formula is H202 (hydrogen peroxide, known as hydrogen peroxide)

Explanation:

100%----34g

5, 9783%---X= (5, 9783%x 34g)/100% =2 g

1g---1 atom of H

2g----x= 2g x 1 atom of H/1g = 2 atom of H

100%----34g

94, 0217%---X= (94,0217%x 34g)/100% =32 g

16g---1 atom of 0

32g----x= 32g x 1 atom of 0/16g = 2 atom of 0

5 0
3 years ago
Explain why warm nitric acid is used​
Schach [20]

Answer:

Lead is added to warm dilute nitric acid. When the carbonate has reacted with the warm acid, more carbonate is added until the carbonate is in excess.

Explanation:

8 0
2 years ago
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