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DanielleElmas [232]
2 years ago
6

Three point charges, two positive and one negative, each having a magnitude of 20 C are placed at the vertices of an equilateral

triangle (30 cm on a side). What is the magnitude of the electrostatic force on the negative charge?
Physics
1 answer:
Daniel [21]2 years ago
5 0

The resultant force on the positive charge  is mathematically given as

X=40N

<h3>What is the magnitude of the electrostatic force on the negative charge?</h3>

Question Parameters:

Three-point charges, two positive and one negative, each having a magnitude of 20

Generally, the -ve charge   is mathematically given as

Q+=\sqrt{x^2+x^2+2x.xcos120}\\\\Q+=\sqrt{2x^2+2x*(1/2)}

Q+=X

Therefore

x=\frac{Kq1q2}{r2}\\\\x=\frac{9*10^9*20*10^{-6}*20*10^{-6}}{(30*10^-2)^2}

X=40N

For more information on Force

brainly.com/question/26115859

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