Since in the forward reaction, H2S is giving a proton away (being the acid) and then CH3NH2 accepting that proton given (being the base).
The reactant in a chemical process known as the limiting reactant controls how much product can be produced. When the limiting reactant is completely used up, the reaction will come to an end.
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Find the limiting reactant ?</h3>
- As a result of 1 mol Sb4O6 reacting with 6 mol H2SO4, only 0.1 mol Sb4O6 reacts with 0.6 mol H2SO4, leaving only 0.5 mol H2SO4. This indicates that H2SO4 is the limiting reactant and Sb4O6 is present in excess.
- According to your equation, which is balanced, 0.1 mol Sb4O6 should react with 0.6 mol H2SO4, yet there is only 0.5 mol H2SO4 on hand.
- Therefore, only.083 mol of Sb4O6 are reacted.
- The reactant that is present in the limiting amount—the limiting reactant—determines the extent to which a chemical reaction occurs.
- The trick is really quite easy! We employ an augmented matrix to hold the data derived from the balancing equation Sb4O6 + 6H2SO4 --> 2Sb2(SO4)3 + 6H2O.
- Although you are provided 0.5 mol of H2SO4, the reaction requires 0.6 mol. Therefore, the limiting reactant is H2SO4.
- Only 0.0833 mol of Sb4O6 is required, but you have 0.1 mol. Sb4O6 is therefore the extra reactant.
To learn more about limiting reactant refer to:
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Answer:
unsaturated fatty acid are liquid in nature, posses multiple bond in it's structure where as saturated fatty acid are solid in nature, have only single bonds in it's structure.
2Ca + O2 = 2CaO
First, determine which is the excess reactant
72.5 g Ca (1 mol) =1.8089725036
(40.078 g)
65 g O2 (1 mol) =2.0313769611
(15.999g × 2)
Since the ratio of to O2 is 2:1 in the balanced reaction, divide Ca's molar mass by 2 to get 0.9044862518. this isn't necessary because Ca is already obviously the limiting reactant. therefore, O2 is the excess reactant.
Now do the stoichiometry
72.5 g Ca (1 mol Ca) (1 mol O2)
(40.078 g Ca)(2 mol Ca)(31.998g O2)
=0.0282669621 g of O2 left over
its the oceam which is blue in color so
