Question

a bus is moving with a constant velocity 10m/s along horizontal rode. a man standing inside bus throws ball virtically upward with valocity 8 m/sec WRT tohimself and cathes the ball .the magnitude of displacment of ball WTR ground will be​

Answer 1

Answer:

16.3 m

Explanation:

v₀ = 8 m/s

v = -8 m/s

a = -9.8 m/s²

Find: t

v = at + v₀

(-8 m/s) = (-9.8 m/s²) t + (8 m/s)

t = 1.63 s

The displacement of the ball with respect to the ground is:

x = vt

x = (10 m/s) (1.63 s)

x = 16.3 m

Round as needed.