Answer:
Explanation:
Acceleration is defined as the change in velocity divided by the time it took to produce such change. The formula then reads:
Where Vf is the final velocity of the object, (in our case 80 m/s)
Vi is the initial velocity of the object (in our case 0 m/s because the object was at rest)
and t is the time it took to change from the Vi to the Vf (in our case 0.05 seconds.
Therefore we have:
Notice that the units of acceleration in the SI system are 
(meters divided square seconds)
Answer:
230 N
Explanation:
At the lowest position , the velocity is maximum hence at this point, maximum support force T is given by the branch.
The swinging motion of the ape on a vertical circular path , will require
a centripetal force in upward direction . This is related to weight as follows
T - mg = m v² / R
R is radius of circular path . m is mass of the ape and velocity is 3.2 m/s
T = mg - mv² / R
T = 8.5 X 9.8 + 8.5 X 3.2² / .60 { R is length of hand of ape. }
T = 83.3 + 145.06
= 228.36
= 230 N ( approximately )
Answer:
a)V=18.35 m/s (South -East)
b) t =7.41 m/s
c)D= 66.70 m
Explanation:
Given that
Velocity of boat in east direction = 16 m/s
Velocity of river = 9 m/s
a)The resultant velocity V
V=18.35 m/s (South -East)
b)
We know that
Distance = Velocity x time
Lets t time takes to cross the river
136 = 18.35 x t
t =7.41 m/s
c)
The distance covered downstream
We know that
Distance = Velocity x time
t= 7.41 s
D= 7.41 x 9 m
D= 66.70 m
6: Short way: it cannot be 2.5, 3, or 5 because up to 5 seconds it only has positive velocity so it must be moving forwards.
Long Way: Velocity is in m / s, multiply that by time (s) to get m or displacement. From 0->5 you have a triangle under the curve, (1/2)(5)(20) = 50 meters displaced positive, you need to then look when velocity is under the curve and use a similar equation to solve for the area but make the answer negative. Find the point where it equals -50 and that is where it will have returned.
Answer to 6: B
7. I cannot see the problem enough to answer this. Just know if the line is above 0 velocity is positive so it is moving the direction it started, when it goes below 0 velocity is negative so it is moving opposite direction it started.
8. Accelration is change in velocity. Whatever the slope of the velocity graph is acceleration. At t=8 the slope is 0 because it is not going up or down.
Answer to 8: A
