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3 years ago

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a car slows down from 22 m/s to 3 m/s at a constant rate of 3.5 m/s squared. how many seconds are required before the car is tra

veling at 3 m/s?

1 answer:

Stolb23 [73]3 years ago

6 0

Answer:

9.05 s

Explanation

v=u+at

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A 32-n force acts on a small mass in the positive x-direction. a 26-n force also acts on it in the negative x-direction. what is

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Equilibrium force is the force that will keep the small mass in place, hence no movement must be made. So we know that 32 N of force is acted towards the positive direction so +32 N. Which is counteracted by 26 N force so:

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Answer:

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3 years ago

Read 2 more answers

A 65.0-kg runner has a speed of 5.20 m/s at one instant dur- ing a long-distance event. (a) What is the runner’s kinetic energy

vladimir2022 [97]

Answer:

a)KE=878.8 J

b)W=2636.4 J

Explanation:

Given that

mass ,m = 65 kg

Initial speed ,u = 5.2 m/s

a)

We know that kinetic energy KE is given as follows

$KE=\dfrac{1}{2}mu^2$

m=mass

u=velocity

Now by putting the values in the above equation we get

$KE=\dfrac{1}{2}\times 65\times 5.2^2\ J$

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b)

We know that

Work done by all forces = Change in the kinetic energy

The final velocity , v= 2 u = 2 x 5.2 m/s

v= 10.4 m/s

$W=\dfrac{1}{2}mv^2-\dfrac{1}{2}mu^2$

Now by putting the values in the above equation we get

$W=\dfrac{1}{2}\times 65\times 10.4^2-\dfrac{1}{2}\times 65\times 5.2^2\ J$

W=2636.4 J

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b)W=2636.4 J

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2 years ago

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Answer:

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C = s

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