Answer: 83.3 W
Explanation: I think, I’m not sure. If I’m wrong correct me ;)
Part a)
in horizontal direction there is no gravity or no other acceleration
so in horizontal direction the speed of clam will remain same
![v_x = 2.70 m/s](https://tex.z-dn.net/?f=v_x%20%3D%202.70%20m%2Fs)
Part b)
In vertical direction we can use kinematics
![v_f = v_i + at](https://tex.z-dn.net/?f=v_f%20%3D%20v_i%20%2B%20at)
![v_f = 0 + 2.1 * 9.8](https://tex.z-dn.net/?f=v_f%20%3D%200%20%2B%202.1%20%2A%209.8)
![v_f = 20.6 m/s](https://tex.z-dn.net/?f=v_f%20%3D%2020.6%20m%2Fs)
part c)
if the speed of crow will be increased then the horizontal speed of the clam will also increase but there is no change in the vertical speed
Answer:
1➡️ this is the method of decomposition
2➡️ H2 and O2
3➡️ b
sorry if I am wrong
Answer:
A 1.0 min
Explanation:
The half-life of a radioisotope is defined as the time it takes for the mass of the isotope to halve compared to the initial value.
From the graph in the problem, we see that the initial mass of the isotope at time t=0 is
![m_0 = 50.0 g](https://tex.z-dn.net/?f=m_0%20%3D%2050.0%20g)
The half-life of the isotope is the time it takes for half the mass of the sample to decay, so it is the time t at which the mass will be halved:
![m'=\frac{50.0 g}{2}=25.0 g](https://tex.z-dn.net/?f=m%27%3D%5Cfrac%7B50.0%20g%7D%7B2%7D%3D25.0%20g)
We see that this occurs at t = 1.0 min, so the half-life of the isotope is exactly 1.0 min.
Answer:
about 19.6° and 73.2°
Explanation:
The equation for ballistic motion in Cartesian coordinates for some launch angle α can be written ...
y = -4.9(x/s·sec(α))² +x·tan(α)
where s is the launch speed in meters per second.
We want y=2.44 for x=50, so this resolves to a quadratic equation in tan(α):
-13.6111·tan(α)² +50·tan(α) -16.0511 = 0
This has solutions ...
tan(α) = 0.355408 or 3.31806
The corresponding angles are ...
α = 19.5656° or 73.2282°
The elevation angle must lie between 19.6° and 73.2° for the ball to score a goal.
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I find it convenient to use a graphing calculator to find solutions for problems of this sort. In the attachment, we have used x as the angle in degrees, and written the function so that x-intercepts are the solutions.