Explanation:
A chemical equilibrium is defined as the state of reaction in which the rate of forward reaction is equal to the rate of backward reaction.
When Q > 
, then it means that the reaction is proceeding in the backward reaction. Whereas if Q < , then it means that the reaction is proceeding in the forward direction. Hence, formation of products will be favored.
On the other hand, if Q = , then it means reaction is at equilibrium.
At equilibrium, it is not necessary that the concentrations of products divided by the concentrations of reactants equals one.
Thus, we can conclude that the statement for a chemical system at equilibrium, the forward and reverse rates of reaction are equal, is correct.
I believe it lies in the 3rd Quadrent
laboratory stock solution is 1.50 M NaOH. Calcul. Show transcribed image text A laboratory stock solution is 1.50 M NaOH. Calculate the volume of this stock solution that would be needed to prepare 300. ml
Explanation:
(a) Formula that shows relation between 
and 
is as follows.
Here, 
= 1
Putting the given values into the above formula as follows.
= 
= 
= 0.01316
(b) As the given reaction equation is as follows.
As there is only one gas so
,
![p[CO_{2}] = K_{p}](https://tex.z-dn.net/?f=p%5BCO_%7B2%7D%5D%20%3D%20K_%7Bp%7D)
= 1.20
Therefore, pressure of 
in the container is 1.20.
(c) Now, expression for for the given reaction equation is as follows.
![K_{c} = \frac{[CaO][CO_{2}]}{[CaCO_{3}]}](https://tex.z-dn.net/?f=K_%7Bc%7D%20%3D%20%5Cfrac%7B%5BCaO%5D%5BCO_%7B2%7D%5D%7D%7B%5BCaCO_%7B3%7D%5D%7D)
= 
= \frac{x^{2}}{(a - x)}[/tex]
where, a = initial conc. of 
= 
= 0.023 M
0.0131 = 
x = 0.017
Therefore, calculate the percentage of calcium carbonate remained as follows.
% of remained = 
= 75.46%
Thus, the percentage of calcium carbonate remained is 75.46%.
