441 g CaCO₃ would have to be decomposed to produce 247 g of CaO
<h3>Further explanation</h3>Reaction
Decomposition of CaCO₃
CaCO₃ ⇒ CaO + CO₂
mass CaO = 247 g
mol of CaO(MW=56 g/mol) :
From equation, mol ratio CaCO₃ : CaO = 1 : 1, so mol CaO :
mass CaCO₃(MW=100 g/mol) :
Answer:
Explanation:
Hello!
In this case, considering that the Gay-Lussac's law allows us to relate the temperature-pressure problems as directly proportional relationships:
Thus, for the initial pressure and temperature in kelvins the final temperature in kelvins, we compute the final pressure as:
Best regards!