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2 years ago

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Consider the type of plant in which edible spoons and other disposable spoons would be produced. What systems would have to be i

ncluded in that location? What models or tools might chemists use to make an edible spoon that functions like a plastic spoon?

1 answer:

Amiraneli [1.4K]2 years ago

4 0

The plants are on the edible spoons

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The structure of Ferrarrisite Ca5(HAs O4)2(AsO4)2

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3 years ago

What is the molar mass of water (H2O)?

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Answer:

The molar mass is: 18.02 g/mol.

Explanation:

Mass of two moles of Hydrogen atoms (H2) = 2x 1 g/mol = 2 g/mol.

Mass of one mole of water (H2O) = 2 g/mol + 16 g/mol = 18 g/mol.

1 mole of Hydrogen= 1.01, so if we have 2 moles of it here, that would be 2.02.

1 mole of Oxygen (that's all we have here)= 16.00

Once you add the two together (2.02+16.00), you will get 18.02.

I hope this made sense! Have a great day!

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3 years ago

A solution is created by dissolving 13.0 grams of ammonium chloride in enough water to make 295 mL of solution. How many moles o

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Answer:

(a) Moles of ammonium chloride = 0.243 moles

(b) $Molarity_{ammonium\ chloride}=0.824\ M$

(c) 60.68 mL

Explanation:

(a) Mass of ammonium chloride = 13.0 g

Molar mass of ammonium chloride = 53.491 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{13.0\ g}{53.491\ g/mol}$

<u>Moles of ammonium chloride = 0.243 moles</u>

(b) Moles of ammonium chloride = 0.243 moles

Volume = 295 mL = 0.295 L ( 1 mL = 0.001 L)

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

$Molarity_{ammonium\ chloride}=\frac{0.243}{0.295}$

$Molarity_{ammonium\ chloride}=0.824\ M$

(c) Moles of ammonium chloride = 0.0500 moles

Volume = ?

Molarity = 0.824 M

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

$0.824\ M=\frac{0.0500}{Volume}$

<u>Volume = 0.05 / 0.824 L = 0.06068 L = 60.68 mL</u>

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