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V125BC [204]
4 years ago
13

Periodic trends vary as we move across the periodic table. In general, as you move across a row in the periodic table A) ionic s

ize increases. B) atomic radius decreases. C) nuclear charge decreases. D) ionization energy decreases.
Physics
2 answers:
RSB [31]4 years ago
8 0
<span>In general, as you move across a row in the periodic table, B. atomic radius decreases.
This is because there is a stronger attraction between outermost electrons and nucleus, which is why the radius between them becomes smaller. 
</span>
uranmaximum [27]4 years ago
8 0
Generally, as one move across a row in the periodic table, atomic radius decreases. The correct option is B.
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Mrs. Brown's class is studying magnets and electricity. At the end of the unit Claire states that magnets and electricity are bo
Gwar [14]

Answer:

Magnets can create electricity and electricity can create a magnetic force.

Both electric charges and magnets do not have to touch an object in order to exert a force on it.

Electromagnets use electricity to create a magnetic force.

Explanation:

7 0
3 years ago
Read 2 more answers
The graph below shows the velocity of a car over time.
jekas [21]

Answer:

D. Calculate the area under the graph.

Explanation:

The distance made during a particular period of time is calculated as (distance in m) = (velocity in m/s) * (time in s)

You can think of such a calculation as determining the area of a rectangle whose sides are velocity and time period. If you make the time period very very small, the rectangle will become a narrow "bar" - a bar with height determined by the average velocity during that corresponding short period of time. The area is, again, the distance made during that time. Now, you can cover the entire area under the curve using such narrow bars. Their areas adds up, approximately, to the total distance made over the entire span of motion. From this you can already see why the answer D is the correct one.

Going even further, one can make the rectangular bars arbitrarily narrow and cover the area under the curve with more and more of these. In fact, in the limit, this is something called a Riemann sum and leads to the definition of the Riemann integral. Using calculus, the area under a curve (hence the distance in this case) can be calculated precisely, under certain existence criteria.

3 0
4 years ago
Read 2 more answers
Like the filters falling through the air, a car on the freeway represents an object with a high Reynolds number traveling throug
Goshia [24]

Answer:

ΔF=125.22 %

Explanation:

We know that drag force on the car given as

F_D=\dfrac{1}{2}\rho C_DA v^2

C_D=Drag coefficient

A=Projected area

v=Velocity

ρ=Density

All other quantity are constant so we can say that drag force and velocity can be given as

\dfrac{F_D_1}{F_D_2}=\dfrac{v_1^2}{v_2^2}

Now by putting the values

\dfrac{F_D_1}{F_D_2}=\dfrac{v_1^2}{v_2^2}

\dfrac{F_D_1}{F_D_2}=\dfrac{50^2}{75^2}

\dfrac{F_D_1}{F_D_2}=0.444

Percentage Change in the drag force

\Delta F=\dfrac{F_D_2-F_D_1}{F_D_1}\times 100

\Delta F=\dfrac{F_D_2-0.444F_D_2}{0.444F_D_2}\times 100

\Delta F=\dfrac{1-0.444}{0.444}\times 100

ΔF=125.22 %

Therefore force will increase by 125.22  %.

3 0
3 years ago
Ellie has two wire circuits, each connected to its own 6 V battery. One circuit has a resistance of 0.80 Ω. The other circuit ca
Vikentia [17]

The second circuit with 4.5 A current has more resistance.

Explanation:

potential difference= 6 V

resistance of first circuit=0.80 Ω

for second circuit, current= i=4.5 A

using Ohm's law V= i R

6=4.5 R

R=1.33 Ω

So the second circuit has a greater resistance.

6 0
3 years ago
A 98.0 N grocery cart is pushed 12.0 m along an aisle by a shopper who exerts a constant horizontal force of 40.0 N. If all fric
Digiron [165]

Answer:

9.8 m/s

Explanation:

The work done by the force pushing the cart is equal to the kinetic energy gained by the cart:

W=K_f -K_i

where

W is the work done

K_f is the final kinetic energy of the cart

K_i is the initial kinetic energy of the cart, which is zero because the cart starts from rest, so we can write:

W=K_f

But the work is equal to the product between the pushing force F and the displacement, so

W=Fd=(40.0 N)(12.0 m)=480 J

So, the final kinetic energy of the cart is 480 J. The formula for the kinetic energy is

K_f=\frac{1}{2}mv^2 (1)

where m is the mass of the cart and v its final speed.

We can find the mass because we know the weight of the cart, 98.0 N:

m=\frac{F_g}{g}=\frac{98.0 N}{9.8 m/s^2}=10 kg

Therefore, we can now re-arrange eq.(1) to find the final speed of the cart:

v=\sqrt{\frac{2K_f}{m}}=\sqrt{\frac{2(480 J)}{10 kg}}=9.8 m/s



7 0
3 years ago
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