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3 years ago

Compare the roles of mitochondria and chloroplasts in plant and animal cells

1 answer:

5 0

Mitochondria help take energy from sugar or glucose and convert it into a simpler form, called ATP, that the cell can more easily use. This process is called cellular respiration, and the mitochondria plays a central role in it.Mitochondria are composed of two membranes.An outer membrane covers the organelle like a skin, protecting it.An inner membrane, that is folded over again and again to create a layered structure called crista, which is studded with proteins. The fluid inside these folds is called the matrix.Chloroplasts are very similar to mitochondria, but are found only in the cells of plants and some algae. Like mitochondria, chloroplasts produce food for their cells. Chloroplasts help turn sunlight into food that can be used by the cell, a process known as photosynthesis.

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Why is sustainable use important?

marusya05 [52]

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3 years ago

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SCORPION-xisa [38]

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3 years ago

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A seamount is an isolated land mass rising from the ocean floor.<br> a. True<br> b. False

iris [78.8K]

The answer is A, True.

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2 years ago

Using Gauss's law, calculate the electric field at a point distance s from a long wire bearing uniform charge density. i need he

11111nata11111 [884]

Answer:

E = 2k $\frac{\lambda}{ r}$

Explanation:

Gauss's law states that the electric flux equals the wax charge between the dielectric permeability.

We must define a Gaussian surface that takes advantage of the symmetry of the problem, let's use a cylinder with the faces perpendicular to the line of charge. Therefore the angle between the cylinder side area has the same direction of the electric field which is radial.

Ф = ∫ E . dA = E ∫ dA = q_{int} /ε₀

tells us that the linear charge density is

λ = q_ {int} /l

q_ {int} = l λ

we substitute

E A = l λ /ε₀

is area of cylinder is

A = 2π r l

we substitute

E = $\frac{ l \ \lambda}{ \epsilon_o \ 2\pi \ r \ l }$

E = $\frac{\lambda}{ 2\pi \epsilon_o \ r}$

the amount

k = 1 / 4πε₀

E = 2k $\frac{\lambda}{ r}$

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2 years ago

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luda_lava [24]

What was the answer?

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