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Harrizon [31]
3 years ago
8

With a mass of 109 kg, Baby Bird is the smallest monoplane ever

Physics
1 answer:
OLga [1]3 years ago
4 0

Total resultant velocity=5.11-3.27=1.84m/s

  • m_1=61.4kg
  • m_2=109kg
  • v_1=1.84m/s
  • v_2=?

\\ \sf\longmapsto ∆P=P

\\ \sf\longmapsto m_1v_1=m_2v_2

\\ \sf\longmapsto v_2=\dfrac{m_1v_1}{m_2}

\\ \sf\longmapsto v_2=\dfrac{61.4(1.84)}{109}

\\ \sf\longmapsto v_2=112.976/109

\\ \sf\longmapsto v_2\approx 1.3m/s

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Cyclotrons are widely used in nuclear medicine for producing short-lived radioactive isotopes. These cyclotrons typically accele
lyudmila [28]

Answer:

Part a)

v = 3.16 \times 10^7 m/s

Part b)

r = 0.166 m

Explanation:

Part a)

As we know that the energy of the Hydride ion is given as

E = 5 MeV

here we have

\frac{1}{2}mv^2 = 5\times 10^6(1.6 \times 10^{-19})

also we know that

m = 1.6 \times 10^{-27} kg

now we have

v = \sqrt{\frac{2 \times 5 \times 10^6(1.6 \times 10^{-19}}{1.6\times 10^{-27}}

v = 3.16 \times 10^7 m/s

Part b)

As we know that magnetic force on the charge is centripetal force

so we have

qvB = \frac{mv^2}{r}

so we have

r = \frac{mv}{qB}

so we have

r = \frac{1.6 \times 10^{-27}(3.16 \times 10^7)}{(1.6 \times 10^{-19}) 1.9}

r = 0.166 m

4 0
3 years ago
Someone please please help me with this.
Softa [21]
600 g=.6 kg
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4 0
3 years ago
Your EMS system covers a large area. For reliable transmission between mobile and portable​ radios, which of the following is​ e
Effectus [21]

Answer:

Repeaters

Explanation:

EMS are communication systems that coordinates emergency medical care among ambulances, 911 (telephone) dispatch centers, and hospital emergency departments. According to my research on EMS systems, I can say that based on the information provided within the question you would need Repeaters. These are a piece of hardware that repeats and extends a signal so that it reaches a greater distance.

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

5 0
3 years ago
An astronaut is in equilibrium when he is positioned 140 km from the center of asteroid X and 581 km from the center of asteroid
mariarad [96]

Answer:

0.05806

Explanation:

m_x = Mass of asteroid x

m_y = Mass of asteroid y

r_x = Distance from asteroid x = 140 km

r_y = Distance from asteroid y = 581 km

m = Mass of asteroid

Force of gravity between asteroid x and the astronaut

F_1=\frac{Gm_xm}{r_x^2}\\\Rightarrow F_1=\frac{Gm_xm}{140^2}

Force of gravity between asteroid x and the astronaut

F_2=\frac{Gm_ym}{r_y^2}\\\Rightarrow F_2=\frac{Gm_ym}{581^2}

Here these two forces are equal as they are in equilibrium

\frac{Gm_xm}{140^2}=\frac{Gm_ym}{581^2}\\\Rightarrow \frac{m_x}{140^2}=\frac{m_y}{581^2}\\\Rightarrow \frac{m_x}{m_y}=\frac{140^2}{581^2}\\\Rightarrow \frac{m_x}{m_y}=0.05806

The ratio of the masses of the asteroid is 0.05806

4 0
3 years ago
What is an example of kinetic energy due to gravity?
faust18 [17]

Answer:

An example of kinetic energy due to gravity can be a ball held in the air (Kinetic energy is energy an object has because of it's motion.).

Explanation:

4 0
4 years ago
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