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notka56 [123]
3 years ago
5

In an experiment 25.0 mL of 0.100 M KI was diluted to 50.0 mL. Calculate the molarity of the diluted solution

Chemistry
1 answer:
Anna11 [10]3 years ago
3 0

Answer:

The molarity is "0.050 M".

Explanation:

The given values are:

M1 = 0.100 M

M2 = ?

V1 = 25.0 mL

V2 = 50.0 mL

As we know,

⇒ M1\times V1=M2\times V2

Or,

⇒ M2=\frac{M1\times V1}{V2}

By putting the values, we get

          =\frac{0.100\times 25}{50}

          =\frac{2.5}{50}

          =0.05 \ M

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See explanation

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A sample of hydrated magnesium sulfate (MgSO4)
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Let the formula for the hydrated magnesium sulphate be MgSO4.xH2O

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