Question

In one football game, a team scored 24 points with a combination of six-point touchdowns, three-point field goals, and one-point "extra points." They made 2 more touchdowns than field goals, and 3 times as many "extra points" as field goals. Let x be the number of touchdowns, y be the number of field goals, and z be the number of "extra points." Write a system of equations that can be solved to find how many touchdowns, field goals, and "extra points" the team made. Do not solve your system.

Answer 1

Given:

Total score = 24 points

They made 2 more touchdowns than field goals, and 3 times as many "extra points" as field goals.

To find:

The system of equations for the given problem.

Solution:

Let x be the number of touchdowns.

y be the number of field goals.

z be the number of "extra points."

Total score is 24 points. So,

$x+y+z=24$

They made 2 more touchdowns than field goals.

$x=y+2$

They made 3 times as many "extra points" as field goals.

$z=3y$

Therefore, the required system of equation is

$x+y+z=24$

$x=y+2$

$z=3y$