a snail can move approximately 0.30 meters per minute.How many meters can the snail cover in 15 minutes ?
1 answer:
You might be interested in
Answer:
The distance between the two slits is 40.11 μm.
Explanation:
Given that,
Frequency
Distance of the screen l = 88.0 cm
Position of the third order y =3.10 cm
We need to calculate the wavelength
Using formula of wavelength
where, c = speed of light
f = frequency
Put the value into the formula
We need to calculate the distance between the two slits
Where, m = number of fringe
d = distance between the two slits
Here,
Put the value into the formula
Hence, The distance between the two slits is 40.11 μm.
Answer:
Explanation:
In the x direction the force will be
½(-w₀)L/2 = -¼w₀L
acting ⅔(L/2) = L/3 below the x axis.
In the y direction the force will be
½(-w₀)L + ½w₀L/2 = -¼w₀L
the magnitude of the resultant will be
F = w₀L √((-¼)² + (-¼)²) = w₀L√⅛
in the direction
θ = arctan(-¼w₀L / -¼w₀L) = 225°
to find the distance, we balance moments
(w₀L√⅛)[d] = ½(w₀)L[⅔L] + ¼w₀L[⅔L/2] - ¼w₀L[L - ⅓L/2]
(√⅛)[d] = ½ [⅔L] + ¼ [⅔L/2] - ¼ [L - ⅓L/2]
(√⅛)[d] = ½[⅔L] + ¼[⅔L/2] - ¼[L - ⅓L/2]
(√⅛)[d] = ⅓L + ⅟₁₂L - ¼L + ⅟₂₄L
(√⅛)[d] = 5L/24
d = 5L/24 / (√⅛)
d = 5√⅛L/3
The period of a simple pendulum is given by:
where L is the length of the pendulum and
is the gravitational acceleration. As we can see, the period of a simple pendulum depends only on its length.
where L is the length of the pendulum and