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4 years ago

What the answer of this?

Physics

2 answers:

stira [4]4 years ago

7 0

The answer is C. Negative Acceleration

The speed is slowing down which means it has negative acceleration.

Hope this helps!

emmainna [20.7K]4 years ago

4 0

The answer is C, has negative acceleration.

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A pendulum of unknown mass is attached to the ceiling and nearly touches the floor as it completes 6 full cycles in 45 s. At its

lys-0071 [83]

Answer:

a) h = 14 m

b) h = 88 cm

c) f = 0.054 Hz

d) f = 0.13 Hz

Explanation:

a) T = 2π√(L/g)

L = T²g/4π²

L = (45/6)²(9.8) / 4π² = 13.963...

b) ½mv² = mgh

h = v²/2g

h = 4.15²/ (2(9.8)) = 0.87869

c) f = 1/T = 1 / (2π√(14 / 1.62)) = 0.0542

d) f = 6/45 = 0.13333...

6 0

3 years ago

In order to cool 1 ton of water at 20°C in an insulated tank, a person pours 140 kg of ice at –5°C into the water. The specific

salantis [7]

Answer:

$T = 6.31 ^0 C$

Explanation:

1 ton = 907.2 kg

so here heat given by water = heat absorbed by the ice

so by energy balance we will have

$Q_1 = Q_2$

$mL + ms\Delta T_1 + ms\Delta T_2 = ms\Delta T_3$

so we have

$140(2.11)(5) + 140(333.7) + 140(4.18)(T) = 907.2(4.18)(20 - T)$

$48195 + 585.2 T = 75841.9 - 3792.1 T$

$T = \frac{27646.92}{4377.3}$

$T = 6.31 ^0 C$

7 0

3 years ago

at 25°c three moles of gas occupy a volume of 4.0L at 1.9 kpa. if the volume increases to 8.0L what will the new pressure be

ki77a [65]

Answer:0.95kPa

Explanation:

5 0

3 years ago

The force shown in the force vs. time diagram in Figure P6.15 acts on a 1.5-kg object. Find (a) the impulse of the force, (b) th

Eduardwww [97]

(a) The impulse of the force is 8 N.s

(b) The final velocity of the object if it is initially at 5.33 m/s

(c) The final velocity of the object if it is initially moving along the x - axis with velocity of 22.0 m/s is 3.33 m/s

<h3>What is impulse?</h3>

The change in momentum is equal to the product of impact force applied while colliding and time for that impact.

Impulse = F. Δt = m (Vf -Vi)

where, Vf is the final velocity and Vi is the initial velocity.

Given, the force shown in the force vs. time diagram acts on a 1.5-kg object.

(a) Impulse is given by

Impulse = F. Δt

Put the values, we get

Impulse = 2x3 + 1/2 x2x2

Impulse = 6+2 = 8N.s

Thus, the impulse from the graph is 8 N.s

(b)

Impulse= F. Δt = m (Vf -Vi)

Substitute the values into the expression, we get

8 = 1.5 x (Vf - 0)

Vf = 5.33 m/s

Thus, the final velocity of the object if it is initially at 5.33 m/s

(c)

Impulse= F. Δt = m (Vf -Vi)

Substitute the values into the expression, we get

8 = 1.5 x (Vf +2)

Vf = 3.33 m/s

Thus the final velocity of the object if it is initially moving along the x - axis with velocity of 22.0 m/s is 3.33 m/s.

Learn more about impulse.

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4 0

2 years ago

An ant crawls along a sidewalk with a velocity of 0.1 m/s in a direction that is 45 degrees relative to the edge of sidewalk. If

alekssr [168]

First draw a diagram (see attached picture).

We know the any traveled 1 m away from the sidewalk, and since we have a 45-45-90 triangle we know that the horizontal distance traveled is also 1 m. Use a^2+ b^2 = c^2 to find the distance the ant traveled. We get sqrt(2).

V=displacement/time
So 0.1 = sqrt(2) / t
Solve for the to get sqrt(2)/0.1 = 14.14 seconds.

5 0

3 years ago