Answer:
The maximum wavelength of light that could liberate electrons from the aluminum metal is 303.7 nm
Explanation:
Given;
wavelength of the UV light, λ = 248 nm = 248 x 10⁻⁹ m
maximum kinetic energy of the ejected electron, K.E = 0.92 eV
let the work function of the aluminum metal = Ф
Apply photoelectric equation:
E = K.E + Ф
Where;
Ф is the minimum energy needed to eject electron the aluminum metal
E is the energy of the incident light
The energy of the incident light is calculated as follows;

The work function of the aluminum metal is calculated as;
Ф = E - K.E
Ф = 8.02 x 10⁻¹⁹ - (0.92 x 1.602 x 10⁻¹⁹)
Ф = 8.02 x 10⁻¹⁹ J - 1.474 x 10⁻¹⁹ J
Ф = 6.546 x 10⁻¹⁹ J
The maximum wavelength of light that could liberate electrons from the aluminum metal is calculated as;
Answer:
Resultant force = (232.93î + 246.10j) N
x-component of the resultant force = (+232.93î) N
y-component of the resultant force = (+246.1j) N
Explanation:
The net external force on the statue is equal to the resultant force on the statue.
And the resuphant force is a vector sum of all the other forces acting on the statue.
Force 1 = (45î) N
Force 2 = (105j) N
Force 3 = (235cos 36.9°)î + (235 sin 36.9°)j = (187.93î + 141.10j) N
Resultant force = (Force 1) + (Force 2) + (Force 3)
Resultant force = 45î + 105j + (187.93î + 141.10j) = (232.93î + 246.10j) N
Hope this helps!!!
Answer:
45coulombs
Explanation:
Using your equation current=0.9 & time=50secs multiply and your answer is 45. Hope the answer is good enough for u
Answer:
The mass is inversely proportional to the acceleration so the acceleration a1 is twice that acceleration a2

Explanation:
The force of friction and the kinetic force make the law of mass in moving so





The forces are the same however at the moment to determinate the acceleration


are constant because they make the same motion however the difference of mass make the acceleration difference
There are no choices available, however through my research this could be the choices for your question:
a) the speed of light
b) the dimensions of the earth´s orbit
c) the number of Saturn´s moons
<span>d) the use of the telescope
</span>
The most probable answer would be his miscalculations about the dimensions of the Earth's orbit which is why his experiment ultimately failed.