Answer:
0.64 J/g°C
Explanation:
Using the formula;
Q = m × c × ∆T
Where;
Q = amount of heat
m = mass (g)
c = specific heat capacity
∆T = change in temperature (°C)
In this case:
Q (water) = - Q (metal)
mc∆T (water) = - mc∆T (metal)
According to the information in this question,
For water; m = 100g, c = 4.18J/g°C, ∆T = (25°C - 20°C)
For metal; m = 50g, c =?, ∆T = (25°C - 90°C)
mc∆T (water) = - mc∆T (metal)
100 × 4.18 × (25°C - 20°C) = - {50 × c × (25°C - 90°C)}
100 × 4.18 × 5 = - {50 × c × -65}
2090 = -{-3250c}
2090 = 3250c
c = 2090/3250
c = 0.643
c = 0.64J/g°C
Hi Pupil Here's Your answer ::
➡➡➡➡➡➡➡➡➡➡➡➡➡
No, on a circle in going from one point around circular path the displacement is zero but the distance covered is equal to the circumference of the circle.
i.e.
⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅
Hope this helps . . . . . . .
Answer:
4.16m/s²
Explanation:
According to Newtons second law;
Fm is the moving force
is the coefficient of kinetic friction between the child and the slide
m is the mass
g is the acceleration due to gravity
a is the acceleration of the child
Substitute the given values and get the acceleration as shown;
35(9.8)sin27.5 - 0.415(35)(cos27.5) = 35a
158.38-12.88 = 35a
145.49 = 35a
a = 145.49/35
a = 4.16m/s²
Hence the acceleration of the body is 4.16m/s²
Answer:
becouse most of nuclear elements are heave
Explanation:
Answer:
Explanation:
maximum energy of capacitor
E = 1/2 C V ²
C is capacitance of capacitor and V is potential difference
given V = 88 V
E = 2002 x 10⁻⁶ J
Putting the values
2002 x 10⁻⁶ = 1/2 x C x 88²
C = .517 x 10⁻⁶ F .
In the second case
Energy E = 125 x 10⁻⁶ J .
C = .517 x 10⁻⁶
V = ?
E = 1/2 C V ²
125 x 10⁻⁶ = 1/2 x .517 x 10⁻⁶ x V²
V² = 483.55
V = 21.98 V .
