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tekilochka [14]
2 years ago
9

A 9-kg body has three times the kinetic energy of an 4-kg body. Calculate the ratio of the speeds of these bodies.

Physics
1 answer:
Neko [114]2 years ago
3 0

Answer:

 speed 9/speed 4   =   2sqrt3 / 3

Explanation:

KE = 1/2 m v^2

for 9 kg   = 3 * the 4 kg      1/2 (9)va^2   = <u> 3</u>* 1/2 (4) vb^2

va^2 / vb^2 = 3*  1/2 (4) / (1/2 *9)

                      6 / 4.5

va / vb = sqrt (6/4.5) =  2sqrt3 /3

ratio of the 9 speed  to the speed of the 4   is  2 sqrt 3 /3

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Answer:

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0.484*m*v_{i} = \frac{0.320744*m*v^2_{i} }{V^2} *V  \\0.484 = 0.320744*\frac{v_{i} }{V} \\\\V = 0.663*v_{i}

Using Eq 1

0.484m*v_{i} = M* 0.663v_{i}\\\\M = 0.730*m

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