Answer:
to the left.
Explanation:
We can use the equation
where v is the velocity at time t and
the velocity at
. Since we want the acceleration we write this equation as:
![a=\frac{v-v_0}{t-t_0}](https://tex.z-dn.net/?f=a%3D%5Cfrac%7Bv-v_0%7D%7Bt-t_0%7D)
Considering the <em>direction to the right as the positive one</em>, we have
at
, and
at
, so we substitute:
![a=\frac{v-v_0}{t-t_0}=\frac{(-8m/s)-(5m/s)}{(10s)-(8s)}=\frac{-13m/s}{2s}=-6.5m/s^2](https://tex.z-dn.net/?f=a%3D%5Cfrac%7Bv-v_0%7D%7Bt-t_0%7D%3D%5Cfrac%7B%28-8m%2Fs%29-%285m%2Fs%29%7D%7B%2810s%29-%288s%29%7D%3D%5Cfrac%7B-13m%2Fs%7D%7B2s%7D%3D-6.5m%2Fs%5E2)
Where the minus sign indicates it is directed to the left.
The force required for the car is 5841 N
Explanation:
First of all, we need to find the acceleration of the car, which is given by:
![a=\frac{v-u}{t}](https://tex.z-dn.net/?f=a%3D%5Cfrac%7Bv-u%7D%7Bt%7D)
where:
v = 27 m/s is the final velocity of the car
u = 0 is the initial velocity (the car starts from rest)
t = 6 s is the time the car takes to accelerate from u to v
Substituting, we find
![a=\frac{27-0}{6}=4.5 m/s^2](https://tex.z-dn.net/?f=a%3D%5Cfrac%7B27-0%7D%7B6%7D%3D4.5%20m%2Fs%5E2)
Now we can find the force needed to accelerate the car; using Newton's second law of motion,
![F=ma](https://tex.z-dn.net/?f=F%3Dma)
where:
F is the net force on the car
m = 1298 kg is the mass of the car
is the acceleration
Substituting, we find:
![F=(1298)(4.5)=5841 N](https://tex.z-dn.net/?f=F%3D%281298%29%284.5%29%3D5841%20N)
Learn more about force and acceleration:
brainly.com/question/11411375
brainly.com/question/1971321
brainly.com/question/2286502
brainly.com/question/2562700
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B. Gamma rays
Gamma rays have highest energy
B. evaporation
c. condensation
They are opposite processes that involve the same transfer of energy
Answer:
I dunno
Explanation:
I really wanted to help you, but then I realized i didnt know how to