Answer:
2.63m
Explanation:
In order to use this expression, we must calculate the values of Velocity (V0) and Velocity(Ve). The initial velocity has only a horizontal component V(0) = V(0x), the final velocity also has a horizontal component since the ball it's at a point of trajectory, V(e) = V(ef). No forces act in the horizontal direction so the momentum of the ball in this direction is conserved, hence, V(0) = V(e)
Therefore, h(e) = h(0) = 2.63m
1 moles CO2, or 44.0095 grams<span>.</span>
If the resistance is ohmic (follows Ohm's law of V=IR), then current should be
I = V/R, where I is current, V is voltage, and R is resistance.
Current in this case will be
I = (120V)/(100Ω)
I = 1.2A
Answer:
The crate was being lifted by a height of 1.48 meters.
Explanation:
In an attempt o move a crate;
Force applied = 2470 N
Work done by the force = 3650 J
We know that the work done is defined as the force used to move an object to a distance.
Given the Force used and the work done by that Force, we need to find out the distance the crate was lifted to.
Work done is defined as:
Work = Force*distance covered in the direction of the force
3650 = 2470*distance
distance = 3650/2470
distance = 1.48 meters