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drek231 [11]
3 years ago
11

Stars located near _____ appears to move in circles when viewed from earth

Physics
1 answer:
Lelu [443]3 years ago
5 0
<span>Stars located near Polaris appears to move in circles when viewed from earth </span>
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Justin depends 600watts if power pushing a car 10m in 5sec how much force did he exert
Natasha_Volkova [10]

Force exerted by Justin=300 N

Here power= 600 W

distance traveled=10 m

time=5 s

power is given by P= Work done/ time

600=work/5

so work= 60x5=3000J

now work done= force* distance

3000=F *10

F= 3000/10

F=300 N

5 0
3 years ago
Train cars are coupled together by being bumped into one another. Suppose two loaded train cars are moving toward one another, t
wolverine [178]

Answer:

final velocity =  0.08585m/s

Explanation:

We are taking train cars as our system. In this system no external force is acting. So we can apply the law of conservation of linear momentum.

The law of conservation of linear momentum states that the total linear momentum of a system remains constant if there is no external force acting on the system. That is total linear momentum before = total linear momentum after

total linear momentum before = linear momentum of first train car + linear momentum of second train car

We know that linear momentum = mv

where,

m = mass

v = velocity

thus,

total linear momentum before = m₁v₁ + m₂v₂

m₁ = mass of first train car = 135,000kg

v₁ = velocity of first train car = 0.305m/s

m₂ = mass of first second car =  100,000kg

v₂ = velocity of second train car =  −0.210m/s

Note: Momentum is a vector. So while adding momentum we should take account of its direction too. Here since second train car is moving in a direction opposite to that of the first one, we have taken its velocity as negative.

total linear momentum before = m₁v₁ + m₂v₂

                                                  = 135,000x0.305 + 100,000x(−0.210)

                                                  = 135,000x0.305 - 100,000x0.210

                                                  = 20,175 kgm/s

Now we have to find total linear momentum after bumping. After the bumping both the train cars will be moving together with a common velocity(say v).

Therefore, total linear momentum after = mv

m = m₁ + m₂ = 135,000 + 100,000 = 235,000

total linear momentum before = total linear momentum after

235,000v = 20,175

v =  \frac{20,175}{235,000}

  = 0.08585m/s

8 0
2 years ago
Read 2 more answers
How do rising temperature affect the process of convection
Papessa [141]

<span>Convection is a process of heat transfer between a surface and a moving fluid. It occurs when the air has a lower temperature than the body, and the body transfers heat through contact with the cold air around it. Air heating causes it to rise. The increase in temperature affects the convection process, since as the warm air rises, the cold air takes its place, thus completing its convection cycle. Example: Wind</span>
4 0
3 years ago
Read 2 more answers
An oscillator consists of a block attached to a spring (k = 500 N/m). At some time t, the position (measured from the system's e
Alex_Xolod [135]

Answer:

a) \omega = 10.407\,\frac{rad}{s}, b) m = 4.617\,kg, c) A = 1.355\,m

Explanation:

a) The system have a simple armonic motion, whose position function is:

x(t) = A\cdot \cos (\omega\cdot t + \phi)

The velocity function is determined by deriving the position function in terms of time:

v(t) = -\omega \cdot A \cdot \sin(\omega\cdot t + \phi)

The acceleration function is found by deriving again:

a(t) = -\omega^{2} \cdot A \cdot \cos (\omega\cdot t + \phi)

Let assume that t = 0\,s. The following nonlinear system is built:

A\cdot \cos \phi = 0.660\,m

-\omega \cdot A \cdot \sin \phi = -12.3\,\frac{m}{s}

-\omega^{2}\cdot A \cdot \sin \phi = -128\,\frac{m}{s^{2}}

System can be reduced by divinding the second and third expressions by the first expression:

\omega \cdot \tan \phi = 18.636\,\frac{1}{s}

\omega^{2}\cdot \tan \phi = 193.94\,\frac{1}{s^{2}}

Now, the last expression is divided by the first one:

\omega = 10.407\,\frac{rad}{s}

b) The mass of the block is:

m = \frac{k}{\omega^{2}}

m = \frac{500\,\frac{N}{m} }{(10.407\,\frac{rad}{s})^{2} }

m = 4.617\,kg

c) The phase angle is:

\phi = \tan^{-1} \left(\frac{18.636\,\frac{1}{s} }{\omega}  \right)

\phi \approx 0.338\pi

The amplitude is:

A = \frac{0.660\,m}{\cos 0.338\pi}

A = 1.355\,m

8 0
3 years ago
Read 2 more answers
What is 13% less of 14 400
GREYUIT [131]
♥ 13%=0.13
14400-0.13
Solve: 14399.87
Answer: <span>14399.87</span>


8 0
2 years ago
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