Answer:
The maximum force on the supporting cable is 80688 N.
The minimum force on the supporting cable is -164 N.
Explanation:
For maximum force movement of elevator is in upward direction. Thus, equation of motion is given by,
ma = T - mg
where m is the mass of elevator
a is acceleration of elevator
g is acceleration due to gravity
T is the maximum tension in the supporting cable
T = ma + mg
T = m (a + g)
T = 4100 ( 0.04g + 9.8)
T = 80688 N
This is the maximum force on the supporting cable.
For minimum force movement of elevator is in downward direction. Thus, equation of motion is given by,
ma = T - mg
where m is the mass of elevator
a= -0.04g is acceleration of elevator because elevator is moving downward
g is acceleration due to gravity
T is the minimum tension in the supporting cable
T = ma + mg
T = m (a + g)
T = 4100 ( 9.8 - 0.04g)
T = -164 N
This is the minimum force on the supporting cable.
