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3 years ago

Which equation has no solution?

Mathematics

1 answer:

Blababa [14]3 years ago

6 0

C is the answer. Adding all the "x" values would give 0, therefore, no solution

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Through:(-1, 2) and (0,2)

Elis [28]

What are you asking for exactly ?

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2 years ago

Which expression is equivalent to

Charra [1.4K]

X^4

Jdnzusjdnekdjdnkdkelef

8 0

3 years ago

Read 2 more answers

PLEASE HELP ME WITH BOTH QUESTIONS<br> THANKS!!

vitfil [10]

First one:

cos(A)=AC/AB=3/4.24

cos(B)=BC/AB=3/4.24

Cos(A)/cos(B)=AC/AB / (BC/AB) = AC/AB * AB/BC = AC/BC=3/3=1

Second one:

To solve this problem, we have to ASSUME AFE is a straight line, i.e. angle EFB is 90 degrees. (this is not explicitly given).

If that's the case, AE is a transversal of parallel lines AB and DE.

And Angle A is congruent to angle E (alternate interior angles).

Therefore sin(A)=sin(E)=0.5

8 0

3 years ago

Find the area of this shape.

aniked [119]

Answer:

Step-by-step explanation:

Bottom triangle

Area = b * height

b = 4 + 4 = 8 cm

h = 5.75

Area = 1/2 * 5.75 * 8

Area = 23 cm^2

Trapezoid

b1 = 8

b2 = 4

h = 2

Area = (b1 + b2)*h/ 2

Area = (8 + 4)*2 /2

Area = 12

Total area = 23 + 12

Total area = 35

7 0

2 years ago

Marty is taking piano lessons. She is going to practice every afternoon. The 1st week she practiced for 11 minutes each day. The

defon

Answer:

$m=7w+4$

Step-by-step explanation:

<u>Linear Modeling</u>

It consist is setting up a linear relationship between two variables, given some experimental data. Only 2 points are needed to set up the equation of a line, but if more than 2 points are used, then the result should use statistical approaches like linear regression to find the best-fit line.

For the question at hand, Marty practices his piano lessons 11 minutes the week #1. It provides the first point (1,11). He practices 25 minutes per day on the third week. It gives us another point (3,25). This is enough to find the equation of a line. The general formula for a line, having two points (m1,w1) (m2,w2) is

$\displaystyle m-m_1=\frac{m_2-m_1}{w_2-w_1}(w-w_1)$

Let's plug in our values

$\displaystyle m-11=\frac{25-11}{3-1}(w-1)$

Simplifying:

$m-11=7w-7$

$\boxed{m=7w+4}$

3 0

3 years ago