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joja [24]
3 years ago
14

An ice cream cone is filled with vanilla and chocolate ice cream at a ratio of 2:3. If the diameter of the cone is 2 inches and

the height is 5 inches, approximately what is the volume of chocolate ice cream in the cone? (round to nearest tenth)
A) 1.6 in3
B) 2.1 in3
C) 3.1 in3
D) 5.2 in3

Please help 35 points if you get this correct real answers only
Mathematics
2 answers:
Tpy6a [65]3 years ago
5 0
Volume of the cone is ⅓πr²h where r= radius=1 in and h=5 in, so volume is 5π/3 cu in. Divide this into 5 equal parts, one part=π/3, so chocolate is 3 parts=π cu in=3.1 cu in = 3.1 cu in approx, answer C.
Ahat [919]3 years ago
5 0

Answer:

Option C. 3.1\ in^{3}

Step-by-step explanation:

Step 1

Find the volume of ice cream

we know that

The volume of the cone is equal to

V=\frac{1}{3}\pi r^{2}h

In this problem we have

r=2/2=1\ in ----> the radius is half the diameter

h=5\ in

substitute

V=\frac{1}{3}\pi (1^{2})(5)=5.2\ in^{3}

Step 2

Find the volume of chocolate ice cream in the cone

Let

x------> volume of vanilla ice cream

y------> volume of chocolate ice cream

we know that

\frac{x}{y} =\frac{2}{3}

x=\frac{2}{3}y -------> equation A

x+y=5.2 -----> equation B

substitute equation A in equation B

\frac{2}{3}y+y=5.2

\frac{5}{3}y=5.2

y=5.2*3/5=3.1\ in^{3}


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Step-by-step explanation:

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Solution:

<u>A few definitions...</u>

  • Rational number - Any integer, fraction, terminating decimal, or repeating decimal is classified as a rational number
  • Irrational number - All the real numbers which are not rational numbers.

<u>Option A - Rational or Irrational?</u>

  • 1/2 + 1/3

Since both are known as fractions, they are rational numbers.

<u>Option B - Rational or Irrational?</u>

  • √2 + 5/2

√2 is classified as an Irrational number because if it is simplified, it does not result in any integer, fraction, terminating decimal, or repeating decimal.

<u>Option C - Rational or Irrational?</u>

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<u>Option D - Rational or Irrational?</u>

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Since this is an integer, this is rational.

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