This system of equations has an infinite number of solutions. Define the solutions algebraically, and allow z to represent all r
eal numbers.
3x − 4y + 4z = 7
x − y − 2z = 2
2x − 3y + 6z = 5
x =
y =
z = all real numbers
1 answer:
Answer:
x = 12z + 1 and y = 10z - 1
Step-by-step explanation:
To solve the system of equations, we can use the substitution method
If we call
3x - 4y + 4z = 7 I
x - y - 2z = 2 II
2x - 3y + 6z = 5 III
Clearing II x = 2 + y + 2z
Now, replacing II in III
2(2 + y + 2z) - 3y +6z = 5
4 + 2y + 4z - 3y + 6z = 5
10z - y = 1 from here y = 10z - 1
Finally, replacing y in I
3x - 4(10z - 1) + 4z = 7
3x -40z + 4 + 4z = 7
3x - 36z = 3
3x = 36z + 3
x = 12z + 1
Done
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The correct option is D.
Answer:
x=30, A=132
Step-by-step explanation:
These 2 angels are alternate interior angles so they are equal
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next step 2:factor out a GFC from each separate binomical
next step 3: factor out the common binomial
