A line in point-slope form has the equation
y = mx + b
where m=slope (increase in y for unit increase in x), and
b=y-intercept (value of y where line cuts y-axis)
The original line is
y=(-1/2)x + 11
so
slope = m = -1/2
Any line perpendicular to a line with slope m has a slope of m1=-1/m
So the slope m1 of the required line
m1 = -1 / (-1/2) = +2
and the required line therefore has an equation of
y=2x+b
Knowing that the line passes through P1=(x1, y1)=(4,-8), we can find b using the point slope form of a line with slope m : (y-y1) = m(x-x1)
where m=+2 as found above.
Substituting values, m=+2, x1=4, y1= -8
y-(-8) = +2(x--4)
simplify
y+8 = 2x-8
=>
y=2x-16 (in point slope form)
Answer:
6
Step-by-step explanation:
-3 -1 +2 +8 = -4+10 = 6
0.825200
(correct me if I’m wrong)
56% = 14 questions
1% = 14 ÷ 56 = 0.25 questions
100% = 0.25 x 100 = 25 questions
Answer: 25 questions.
Answer:
Given that a parallelogram ABCD has sides AB= 6 ft and AX = 3√3
Angle A =30
To find the area of the parallelogram
We have area of parallelogram = base x height
Here base can be taken as side AB = 6 ft
Height = perpendicular distance of AB from vertex X
= AX sin A
= 3√3sin30
=1.5√3
Hence area =6(1.5√3)=9√3ft^2
Read more on Brainly.com - brainly.com/question/12140514#readmore
Step-by-step explanation:
