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goldfiish [28.3K]
3 years ago
15

This speed is measured with respect to the space station the spacecraft was originally launched from. In interstellar space the

gravitational pull from the stars is negligible, because the stars are extremely far. The spacecraft turns its main rocket engine on for a time period of 6.5 hours. The rocket engine provides a thrust of 896 N of force. What is the new speed of the craft after the engine is turned off? The mass of the spacecraft is 1380 kg. The rocket engine is very efficient, it uses only a very small amount of rocket fuel during this whole acceleration process without changing the mass of the craft.
Physics
1 answer:
valentinak56 [21]3 years ago
5 0

Answer:

15193.62 m/s

Explanation:

t = Time taken = 6.5 hours

u = Initial velocity = 0 (Assumed)

m = Mass of rocket = 1380 kg

F = Thrust force = 896 N

v = Final velocity

a = Acceleration of the rocket

Force

F=ma\\\Rightarrow a=\frac{F}{m}\\\Rightarrow a=\frac{896}{1380}\\\Rightarrow a=0.6493\ m/s^2

Equation of motion

v=u+at\\\Rightarrow v=0+0.6493\times 6.5\times 60\times 60\\\Rightarrow v=15193.62\ m/s

The velocity of the rocket after 6.5 hours of thrust is 15193.62 m/s

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#1 Not sure where to start. This is for AP Physics!
yaroslaw [1]

First,

\rho=\dfrac mV

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2.7\,\dfrac{\mathrm g}{\mathrm{cm}^3}=\dfrac{1275\,\mathrm g}V

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When the roll is unfurled, the aluminum will be a rectangular box (a very thin one), so its volume will be the product of the given area and its thickness x. Note that we're assuming the given area is not the actual total surface area of the aluminum box, but just the area of the largest face (i.e. the area of one side of the unrolled sheet of aluminum).

So we have

V=Ax

where A is the given area, so

4.72\,\mathrm m^3=\left(18.5\,\mathrm m^2\right)x

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If we're taking significant digits into account, the volume we found would have been V=470\,\mathrm m^3, in turn making the thickness x=250\,\mathrm{mm}.

8 0
3 years ago
Acceleration increases over time once a force is applied to the object. Given a force of 10.0 Newtons, which mass will have the
Zolol [24]

Mass is indirectly proportional to acceleration, so, lighter the object greater would be it's acceleration...

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6 0
3 years ago
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ioda
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3 years ago
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In the pair of supply and demand equations below, where x represents the quantity demanded in units of a thousand and p the unit
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Answer:

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For the equilibrium quantity the price from both the functions will be equal

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now the equilibrium price can be found out by substituting the equilibrium quantity in any of the equation

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p = -(5)² -3(5) + 80 = 40

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