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3 years ago

6

A girl picks up a bag of apples that are at rest on the floor. How dose the force the girl applies compare to the force of gravi

ty acting on the apples

1 answer:

AysviL [449]3 years ago

6 0

Answer:

When the bag of apples are on the floor, the force of gravity is equal to the force applied in the upward direction.

But when the girl picks up the bag of apples, she applies a force on the bag of apples in the upward direction greater than that of the gravitational force.

Explanation:

Gravitational force for an object is always constant at a specific point. When an object is in the state of rest, there is an equal force opposite to the direction of Gravitational Force.

Now, to lift an object upwards, an external force must be applied that is greater than the force of gravitation.

So, when the girl picks up the bag of apples,

Gravitational Force < Force applied by the girl to lift the bag.

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Explanation:

From the question we are told that

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The maximum extension of the spring is $A = 6.0 \ cm = 0.06 \ m$

The number of oscillation is $n = 30$

The time taken is $t = 20 \ s$

Generally the the angular speed of this oscillations is mathematically represented as

$w = \frac{2 \pi}{T}$

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$T = \frac{t}{n}$

substituting values

$T = \frac{20}{30 }$

$T = 0.667 \ s$

Thus

$w = \frac{2 * 3.142 }{ 0.667}$

$w = 9.421 \ rad/s$

this angular speed can also be represented mathematically as

$w = \sqrt{\frac{k}{m} }$

=> $m =\frac{k }{w^2}$

substituting values

$m =\frac{ 15 }{(9.421)^2}$

$m = 0.169 \ kg$

In SHM (simple harmonic motion )the equation for velocity is mathematically represented as

$v = - Awsin (wt)$

The velocity is maximum when $wt = \(90^o) \ or \ 1.5708\ rad$

$v_{max} = - A* w$

=> $|v_{max} |= A* w$

=> $|v_{max} |= 0.06 * 9.421$

=> $|v_{max} |= 0.5653 \ m/s$

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3 years ago