The answer for the following mention bellow.
- <u><em>Therefore the final temperature of the gas is 260 k</em></u>
Explanation:
Given:
Initial pressure (
) = 150.0 kPa
Final pressure (
) = 210.0 kPa
Initial volume (
) = 1.75 L
Final volume (
) = 1.30 L
Initial temperature (
) = -23°C = 250 k
To find:
Final temperature (
)
We know;
According to the ideal gas equation;
P × V = n × R ×T
where;
P represents the pressure of the gas
V represents the volume of the gas
n represents the no of moles of the gas
R represents the universal gas constant
T represents the temperature of the gas
We know;
= constant
×
= ![\frac{T_{1} }{T_{2} }](https://tex.z-dn.net/?f=%5Cfrac%7BT_%7B1%7D%20%7D%7BT_%7B2%7D%20%7D)
Where;
(
) represents the initial pressure of the gas
(
) represents the final pressure of the gas
(
) represents the initial volume of the gas
(
) represents the final volume of the gas
(
) represents the initial temperature of the gas
(
) represents the final temperature of the gas
So;
= ![\frac{260}{T_{2} }](https://tex.z-dn.net/?f=%5Cfrac%7B260%7D%7BT_%7B2%7D%20%7D)
(
) =260 k
<u><em>Therefore the final temperature of the gas is 260 k</em></u>
<u><em></em></u>