<h2>Answer: 0.00925 mol
</h2>
Explanation:
Moles = # of molecules ÷ Avogadro's Number
= (5.57 × 10²¹ molecules) ÷ (6.022 × 10²³ molecules/mol)
= 0.00925 mol
<h3>∴ the 5.57 x 10²¹ molecules of carbon dioxide ≡ 0.00925 mol</h3>
Answer:
D 4P +3O₂ → 2 P₂O₃
Explanation:
In this problem, we need to convert the mass of phosphorus and oxygen to moles trying to find the ratio of reaction (The moles of P that reacts per mole of O₂):
<em>Moles P:</em>
12.4g P * (1mol P / 31g) = 0.4 moles
<em>Moles O₂:</em>
9.6g * (1mol / 32g) = 0.3 moles
The ratio of reaction is:
0.4 mol / 0.3 mol = 1.33 = 4 moles of P / 3 moles of O₂
That means 4 moles of P react with 3 moles of O₂ and the reaction that represents this ratio is:
<h3>D 4P +3O₂ → 2 P₂O₃</h3>
Answer:
<em>Three (3) of the molecules are polar: </em>
<em> </em>
<em> </em>
<em>.</em>
Explanation:
Polar substances have their elements held together by a covalent bond that contain partially positive and negative charges, which results in a difference in the charges' electronegativity difference (usually ranging between 0.4 and 0.7).
- PCl5 is <u>non-polar</u> with a symmetric geometry
- CoS is <u>polar</u>
- XeO3 is <u>polar</u>, with a trigonal pyramidal molecular geometric
- SeBr2 is <u>polar</u> as the difference their electronegativity is about ).5
Answer:
0.64 g of S
Solution:
The balance chemical equation is as follow,
2 Cu + S ----> Cu₂S
According to equation,
127 g (2 mole) Cu produces = 159 g (1 mole) of Cu₂S
So,
2.54 g Cu will produce = X g of Cu₂S
Solving for X,
X = (2.54 g * 159 g) / 127 g
X = 3.18 g of Cu₂S
Now, it is confirmed that the reaction is 100% ideal. Therefore,
As,
127 g (2 mole) Cu required = 32 g (1 mole) of S
So,
2.54 g Cu will require = X g of S
Solving for X,
X = (2.54 g * 32 g) / 127 g
X = 0.64 g of S
