Since we are ignoring air resistance which is a non-conservative force, the potential energy will be completely converted into kinetic energy, resulting in a final kinetic energy of 
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In a Millikan oil-drop experiment, the condenser plates are spaced 2.00 cm apart, the potential across the plates is 4000 V, the
rise or fall distance is 4.00 mm, the density of the oil droplets is 0.800 g/cm3 , and the viscosity of the air is 1.81 105 kg m1 s 1 . The average time of fall in the absence of an electric field is 15.9 s. The following different rise times in seconds are observed when the field is turned on: 36.0, 17.3, 24.0, 11.4, 7.54. (a) Find the radius and mass of the drop used in this experiment. (b) Calculate the charge on each drop, and show that charge is quantized by considering both the size of each charge and the amount of charge gained (lost) when the rise time changes. (c) Determine the electronic charge from these data. You may assume that e lies between 1.5 and 2.0 1019 C. 7.
1 answer:
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Answer:
15.106 N
Explanation:
From the given information,
The weight of the bucket can be calculated as:
The mass of the water accumulated in the bucket after 3.20s is:
To determine the weight of the water accumulated in the bucket, we have:
For the speed of the water before hitting the bucket; we have:
v = 8.4 m/s
Now, the force required to stop the water later when it already hit the bucket is:
F = 1.68 N
Finally, the reading scale is:
= 7.154 N + 6.272 N + 1.68 N
= 15.106 N