it hasn't been specified which ticket the question's is asking but I'm guessing the price of the adult ones so $30.00
altogether that's two adults and 3 children who all paid a total of $105.00
let's simplify that to algebra
children tickets = c adults tickets = a
3c + 2a = $105.00
we know that 1c is 0.5a because each child ticket is half of an adults one <em>as stated in the question</em>
so in terms of (adults) a: half of 3 meaning 3×0.5= $1.5 meaning 1.5a
so now <em>3c = 1.5a</em>
so we can substitute and have like terms
meaning 1.5a + 2a= $105
3.5a =$105.00
divide by 3.5 on both sides to get a by itself thus the value of a:
a = $30
so each adult tickets cost $30
Answer:
2520
Step-by-step explanation:
Step-by-step explanation:
inscribed angles subtended by the same arc are equal.
the central angle of a circle is twice any inscribed angle subtended by the same arc.
the first statement tells us that the 53° angle as well as y stay the same size no matter where on their arcs (between the 2 points connected to O) they would be. so, we don't need to bother with any line lengths.
the 2nd statement tells us that x = 2×53 = 106°. the 53° and x angles refer to the short arc on the right of the 2 points connected to O.
and y and x refer to the larger arc on the left of the 2 line connected to O. that means according to the second statement : 360-x (the big angle around O) = 2y
so,
360 - 106 = 2y
254 = 2y
y = 127°
This problem cannot be solved unless we are given figure NPQR is a rhombus.
In that case, then all sides are equal, meaning
5x+16=9x-32
Solve for x
9x-5x=16+32
4x=48
x=12
Each side (including PQ) then equals 5x+16=5*12+16=76
