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DanielleElmas [232]
3 years ago
15

A car sitting at a red light begins to accelerate at 2 m/s2 when the light turns green. It continues with this acceleration unti

l it reaches a speed of 20 m/s. It then travels at this speed for another few minutes. How far does the car travel in the first 35 s after the light changes to green
Physics
1 answer:
jek_recluse [69]3 years ago
7 0

Answer:

    x_total = 600 m

Explanation:

This is an exercise and kinematics, let's find the time it takes to reach the velocity  20 m / s

          v = v₀ + a t

           

as part of rest v₀ = 0

          t = v / a

          t = 20/2

          t = 10 s

let's find the distance traveled in this time

          x₁ = vo t + ½ a t2

          x₁ = 0 + ½ 2 10²

          x₁ = 100 m

The remaining time is

          t₂ = 35 - t

          t₂ = 35 - 10

          t₂ = 25 s

as in this range it has a constant speed

          v = x₂ / t₂

          x₂ = v t₂

          x₂ = 20  25

          x₂ = 500 m

the total distance traveled is

           x_total = x₁ + x₂

           x_total = 100 + 500

           x_total = 600 m

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An object is dropped from a height of 75.0 m above ground level. (a) Determine the distance traveled during the first second. (b
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a)Distance traveled during the first second = 4.905 m.

b)Final velocity at which the object hits the ground = 38.36 m/s

c)Distance traveled during the last second of motion before hitting the ground = 33.45 m

Explanation:

a) We have equation of motion

             S = ut + 0.5at²

     Here u = 0, and a = g

              S = 0.5gt²

    Distance traveled during the first second ( t =1 )

              S = 0.5 x 9.81 x 1² = 4.905 m

   Distance traveled during the first second = 4.905 m.

b)  We have equation of motion

            v² = u² + 2as

      Here u = 0, s= 75 m and a = g

           v² = 0² + 2 x g x 75 = 150 x 9.81

           v = 38.36 m/s

      Final velocity at which the object hits the ground = 38.36 m/s

c) We have S = 0.5gt²

                   75 = 0.5 x 9.81 x t²

                    t = 3.91 s

   We need to find distance traveled last second

   That is

          S = 0.5 x 9.81 x 3.91² - 0.5 x 9.81 x 2.91² = 33.45 m

   Distance traveled during the last second of motion before hitting the ground = 33.45 m

       

3 0
3 years ago
a horse runs with an initial velocity of 11m/s and slows to 5.2 m/s over a time interval of 3.1 s what is the horse's average ac
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Answer:

a = change in v / change in time

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= -1.87 m/s^2

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